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2 years ago

Someone plz help me

Mathematics

2 answers:

Fed [463]2 years ago

8 0

Answer:Which one do you need help with

Step-by-step explanation:

Kamila [148]2 years ago

8 0

1. 5 Folder 5 Pen = yes

6 Pen 6 Eraser = Yes

1 Pen 4 Notebook = No

3 Folder 7 Eraser = No

4 Folder 2 Notebook = Yes

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Please help ASAP it’s due today

Westkost [7]

Answer:

1) At least 6.

2) $2194.8

3) $2326.49

4) 38 mph on average.

Step-by-step explanation:

Comment if you do need the steps

7 0

2 years ago

What is the slope in this equation? y = 3x - 5

nikdorinn [45]

Answer:

Step-by-step explanation:

The equation is y=Mx+b where m is the slope and b is the y intercept so m=3 so the slope is 3

4 0

2 years ago

Read 2 more answers

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

The Eatery Restaurant has 200 tables. On a recent evening, there were reservations for 1/10 of the tables. How many tables were

iren2701 [21]

the answer is 20

1/10 of 200 is 200* 1/10 = 200/10 which is 20

5 0

2 years ago

What is the zeros for the equation f(x) =

sergij07 [2.7K]

Answer:

B. and E.

Step-by-step explanation:

6 0

2 years ago

Someone plz help me​

Someone plz help me