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2 years ago

8x -(-5) = 29 To make the equation true, what is the value of x?

Mathematics

2 answers:

olchik [2.2K]2 years ago

6 0

Answer:

Step-by-step explanation:

Because you just have to replace and what would it give = 8(3) -(-5) = 29

snow_tiger [21]2 years ago

5 0

Answer:

x = 3

Step-by-step explanation:

In order to solve this equation, first we need to make the equation easier to read.

So instead of:

8x - (-5) = 29

We will do:

8x + 5 = 29

(Note that we have a plus sign now, because subtracting a negative number is the same as adding a positive number.)

Next we move the 5 to the other side of the equal sign, by subtracting it.

Now we have:

8x = 24

Finally we isolate the x variable, by dividing by 8 on both sides.

(24 ÷ 8 = 3)

Our answer is 3, therefore x = 3.

Hope this helps you :)

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There are three local factories that produce radios. Each radio produced at factory A is defective withprobability .02, each one

diamong [38]

Answer:

The probability is 0.02667

Step-by-step explanation:

Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.

So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

P(D2/D1) = P(D2∩D1)/P(D1)

Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:

$P(D2/D1)_A=\frac{0.02*0.02}{0.02} =0.02$

At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_B=\frac{0.01*0.01}{0.01} =0.01$

Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)_C=\frac{0.05*0.05}{0.05} =0.05$

So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:

P(A)=1/3

P(B)=1/3

P(C)=1/3

Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:

$P(D2/D1)=P(A)P(D2/D1)_A+P(B)P(D2/D1)_B+P(C)P(D2/D1)_C$

P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)

P(D2/D1) = 0.02667

6 0

3 years ago

Subtract. (−8.3x+4)−(3.2x−5) Enter your answer, in simplified form, in the box.

lesya692 [45]

-2.5x is the answer for this question i believe if i did it right'

8 0

3 years ago

Read 2 more answers

PLEASE HELP ASAP, I WILL MARK THE BRAINLIEST

dlinn [17]

Answer:

the answer is c now mark me brainliest please.

Step-by-step explanation:

all sides are congruent and it is a parallelogram.

8 0

3 years ago

Could someone help me rnnn?

GuDViN [60]

Answer:

vertex = (0, -4)

equation of the parabola: $y=3x^2-4$

Step-by-step explanation:

Given:

y-intercept of parabola: -4
parabola passes through points: (-2, 8) and (1, -1)

Vertex form of a parabola: $y=a(x-h)^2+k$

(where (h, k) is the vertex and $a$ is some constant)

Substitute point (0, -4) into the equation:

$\begin{aligned}\textsf{At}\:(0,-4) \implies a(0-h)^2+k &=-4\\ah^2+k &=-4\end{aligned}$

Substitute point (-2, 8) and $ah^2+k=-4$ into the equation:

$\begin{aligned}\textsf{At}\:(-2,8) \implies a(-2-h)^2+k &=8\\a(4+4h+h^2)+k &=8\\4a+4ah+ah^2+k &=8\\\implies 4a+4ah-4&=8\\4a(1+h)&=12\\a(1+h)&=3\end{aligned}$