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rewona [7]
3 years ago
13

Select the correct answer. if f(x) = x^1/2– x and g(x) = 2x^3 –x^1/2-x find f(x) – g(x).

Mathematics
1 answer:
Igoryamba3 years ago
6 0

f(x) - g(x) =  -2x^{3}+2x^{1/2}

<u>Step-by-step explanation</u>:

<u>Given</u> :

  • f(x) = x^{1/2} -x
  • g(x) = 2x^{3} -x^{1/2} -x

f(x) - g(x) = (x^{1/2} -x) - ( 2x^{3} -x^{1/2} -x)

⇒ (x^{1/2} -x-2x^{3}+x^{1/2} +x)

⇒ -2x^{3}+2x^{1/2}

f(x) - g(x) =  -2x^{3}+2x^{1/2}

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Read 2 more answers
Can someone help me with this thanks ​
Ugo [173]

The length of the brace required is 4.3m

What is sine rule?

In a ΔABC a, b and c are the sides and A, B and C are angles then,

\frac{a}{SinA}=\frac{b}{sinB}=\frac{c}{sinC}

We can find the length, l as shown below:

Let AB=3m, BC=2m and AC=l

Let ∠A=25°

So, in ΔABC

\frac{BC}{sinA}=\frac{AB}{sinC}=\frac{AC}{SinB}

\frac{BC}{sinA}=\frac{AB}{sinC}

\frac{2}{sin25}=\frac{3}{sinC}

\angle{C}=sin^{-1}(\frac{3\times sin25}{2} )

∠C=39.34°

∠A+∠B+∠C=180°

∠B=180°-25°-39.34°

∠B=115.66°

\frac{BC}{sinA}=\frac{AC}{SinB}

\frac{2}{sin25}=\frac{l}{sin(115.66)}

l=\frac{2\times sin(115.66)}{sin25}

l=4.2659

Rounding to nearest tenth of meter.

l=4.3m

Hence, the length of the brace required is 4.3m

Learn more about Sine Rule here:

brainly.com/question/25852087

#SPJ1

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2 years ago
In right ∆ABC, m B = 90°, m C = 40°, and BC = 10. What are the other two side lengths of the triangle?
Neporo4naja [7]
I hope this helps you

3 0
3 years ago
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