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Arte-miy333 [17]
3 years ago
6

The radius of a cylindrical gift box is ​(3x+1​) inches. The height of the gift box is twice the radius. What is the surface are

a of the​ cylinder? Write your answer as a polynomial in standard form.
Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

Answer:

56πx² + 36πx + 6π square inches

Step-by-step explanation:

The radius of a cylindrical gift box is ​(3x+1​) inches. The height of the gift box is twice the radius. What is the surface area of the​ cylinder? Write your answer as a polynomial in standard form.

The surface area of a cylinder is given as:

2πr(r + h)

The radius of a cylindrical gift box is ​(3x+1​) inches.

The height of the gift box is twice the radius = 2(3x + 1) inches

= 6x + 2 inches

The surface area of the cylinder is:

= 2 × π × 3x + 1( 3x + 1 + 6x + 2) square inches

= 2 × π × 3x + 1(9x + 3) square inches

= 2π × 3x + 1(9x + 3) square inches

= 6πx + 2π( 9x + 3) square inches

= 6πx (9x + 3) + 2π( 9x + 3) square inches

= 56πx² + 18πx + 18πx + 6π square inches

= 56πx² + 36πx + 6π square inches

The surface area of the​ cylinder is 56πx² + 36πx + 6π square inches

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We know that, zeros are the values at which the values of the function is 0. It means, the points where the graph of function intersect the x-axis are know as zeros of the function.

From the given graph it is clear that, the graph intersect the x-axis at two points.

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3 years ago
A new car is available with standard or automatic transmission, two or four doors, and it is available in 10 exterior colors. Wh
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Answer:

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Step-by-step explanation:

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To find:

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3. Automatic - 2 doors

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