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3 years ago

Express the product as a whole number. 312×28=

Mathematics

1 answer:

Monica [59]3 years ago

3 0

The answer would be 8736

Hope this helps :)

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Which is colder -3 -12 -8 -15

8_murik_8 [283]

Answer:

-15 is colder than the others

Step-by-step explanation:

It is colder because it is in the negatives but it also has a higher absolute value

4 0

3 years ago

D^2(y)/(dx^2)-16*k*y=9.6e^(4x) + 30e^x

MA_775_DIABLO [31]

The solution depends on the value of $k$ . To make things simple, assume $k>0$ . The homogeneous part of the equation is

$\dfrac{\mathrm d^2y}{\mathrm dx^2}-16ky=0$

and has characteristic equation

$r^2-16k=0\implies r=\pm4\sqrt k$

which admits the characteristic solution $y_c=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}$ .

For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be $y_p=ae^{4x}+be^x$ . Then

$\dfrac{\mathrm d^2y_p}{\mathrm dx^2}=16ae^{4x}+be^x$

So you have

$16ae^{4x}+be^x-16k(ae^{4x}+be^x)=9.6e^{4x}+30e^x$
$(16a-16ka)e^{4x}+(b-16kb)e^x=9.6e^{4x}+30e^x$

This means

$16a(1-k)=9.6\implies a=\dfrac3{5(1-k)}$
$b(1-16k)=30\implies b=\dfrac{30}{1-16k}$

and so the general solution would be

$y=C_1e^{-4\sqrt kx}+C_2e^{4\sqrt kx}+\dfrac3{5(1-k)}e^{4x}+\dfrac{30}{1-16k}e^x$

8 0

2 years ago

My question is:

8090 [49]

Uh it's 5? I'm confused

8 0

3 years ago

Read 2 more answers

How do I find the missing side lengths? Someone please help!!!

adell [148]

45°-45°-90°
Hope I could help!

3 0

3 years ago

The volume of a cube is 125 cubic inches. What is the<br> length of one edge of the cube?

Tcecarenko [31]

Step-by-step explanation:

All the edges of a cube have the same length, and the volume of a cube is the length of an edge taken to the third power. So the length of the edge of a cube with a volume of 125 is 5.

6 0

3 years ago