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Sindrei [870]
2 years ago
9

What does measure angle ECF equal?

Mathematics
1 answer:
Anika [276]2 years ago
3 0
The measure angle ECF equals 32°.
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What is the standard deviation of the data set 21 ,6,18,21,20,14,19
VashaNatasha [74]
21 is the answer i think idk try dividing them all or finindng something or look up how to find a standard deviation 


8 0
3 years ago
5. What is the combined weight of the 3/4-lb bags?<br>​
Andrew [12]

The answer would be 3.175 kg

6 0
3 years ago
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Which statement best describes (3 x 4 x6 = 3 x (4 x 6)
Ratling [72]

Answer:

The given statement is,

(3 * 4) * 6 = 3(4 * 6)

To find (3 * 4) * 6

(3 * 4) * 6 = 12 * 6 = 72

To find 3(4 * 6)

3(4 * 6) = 3 * 24 = 72

Step-by-step explanation:

The result of these two expression is same.

Therefore we can conclude that,

Therefore the correct answer is,

The grouping of the factors is changed but the product is the same.

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7 0
2 years ago
Find the GCF 0f 12 and 18
melisa1 [442]

Answer:

  6

Step-by-step explanation:

Using Euclid's algorithm, we divide the larger by the smaller. If the remainder is zero, the divisor is the GCF. Otherwise, we replace the larger with the remainder and repeat.

  18 ÷ 12 = 1 r 6

  12 ÷ 6 = 2 r 0 . . . . the GCF is 6

__

You can also factor the numbers and see what the common factors are.

  18 = 2·3·3

  12 = 2·2·3

The common factors are 2·3 = 6.

In the factorizations, we see 2 to powers of 1 and 2, and we see 3 to powers of 1 and 2. The GCF is the product of the common factors to their lowest powers: (2^1)(3^1) = (2)(3) = 6

8 0
2 years ago
A solid oblique pyramid has a square base with edges measuring x cm. The height of the pyramid is (x + 2) cm. Which expression r
zavuch27 [327]

we know that

the volume of a solid oblique pyramid is equal to

V=\frac{1}{3}*B*h

where

B is the area of the base

h is the height of the pyramid

in this problem we have that

B is a square

B=b^{2}

where

<u>b=x\ cm</u>

so

B=x^{2}\ cm^{2}

h=(x+2)\ cm

substitute in the formula of volume

V=\frac{1}{3}*x^{2}*(x+2)\\ \\V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}

therefore

<u>the answer is</u>

V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}

4 0
2 years ago
Read 2 more answers
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