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2 years ago

My math homework says 32 over 41 equals 96 over blank what is the blank ??

2 answers:

4 0

The blank is 123 because 32/41=96/123.
your multiplying 32 by 3 to get 96.
That means you have to multiply the bottom by 3 too.
41 multiplied by 3 is 123.
And 123 is the blank.

Helga [31]2 years ago

4 0

It is 41x96 then divide by 32. This gives you your answer of 123

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Find the value of the expression below. Express your answer in scientific notation.

nirvana33 [79]

The value of the expression is $8.8 \times 10^{-2}$ .

Solution:

Given expression:

$$\frac{\left(4.8 \times 10^{8}\right)}{\left(1.2 \times 10^{4}\right)} \times\left(2.2 \times 10^{-6}\right)$

<u>To find the value of the given expression:</u>

Using exponent rule: $a^m\times a^n=a^{m+n}$

$$\Rightarrow\frac{\left(4.8 \times 10^{8-6}\right)}{\left(1.2 \times 10^{4}\right)} \times\left(2.2 \right)$

$$\Rightarrow\frac{\left(4.8 \times 10^{2}\right)}{\left(1.2 \times 10^{4}\right)} \times\left(2.2 \right)$

Using exponent rule: $\frac{a^m}{a^n} =a^{m-n}$

$$\Rightarrow\frac{\left(4.8 \times 10^{2-4}\right)}{1.2} \times 2.2$

$$\Rightarrow\frac{\left(4.8 \times 10^{-2}\right)}{1.2} \times 2.2$

Since $\frac{4.8}{1.2}=4$

$$\Rightarrow(4 \times 10^{-2})\times 2.2$

$$\Rightarrow 8.8 \times 10^{-2}$

Hence the value of the expression is $8.8 \times 10^{-2}$ .

7 0

2 years ago

At what root does the graph of f(x)=(x+4)^6(x+7)^5 cross the x axis?

xz_007 [3.2K]

Answer:

f(x) crosses the x-axis, then

f(x)=(x+4)^6(x+7)^5 = 0

=> x+4 =0 or x+7=0

=> x =-4 or x = -7

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2 years ago

The average weight of a newborn panda is 0.2, or 2/10 pound. Between what two integers is the weight of a newborn panda?

sweet-ann [11.9K]

Answer:

$\frac{2}{10}$ lies between 0 and 1.

Step-by-step explanation:

We must have in mind that given average weight of a newborn panda is a non-integer rational number, such that lies between two integer rational number. In other words, this number must satisfy the following condition:

$n < \frac{a}{b} < n +1$ , $n, a, b \in \mathbb{N}_{O}$