Expand (4x-3y)^4 using pascal's triangle ...?

1 answer:

8 0

Using row 4:

coefficients are: 1, 4, 6, 4, 1 

a^4 + a^3b + a^2b^2 + ab^3 + b^4 

Now adding the coefficients: 

1a^4 + 4a^3b + 6a^2b^2 + 4ab^3 + 1b^4 

Substitute a and b: 

a = 4x 

b = -3y 

1(4x)^4 + 4(4x)^3(-3y) + 6(4x)^2(-3y)^2 + 4(4x)(-3y)^3 + 1(-3y)^4 

Now simplify the above: 

256x^4 - 768x^3y + 864x^2y^2 - 432xy^3 + 81y^4

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A company is selling toothpicks. It costs $0.01 to produce each toothpick and a fixed cost of $60 a month for the company. If th

Lapatulllka [165]

Answer:

6,000 toothpicks

Step-by-step explanation:

In this question, we are trying to evaluate the number of toothpicks a company must sell to ensure that the money spent on production is exactly equal to revenue from sales.

What we do is this!

Let’s assign a variable to represent the number of tooth picks sold and produced by the company. Let us call this number x.

First, we evaluate the total amount spent on production of x toothpicks. From the question, we can see that the cost of producing a single toothpick is $0.01, hence, to produce x toothpicks, amount spent asides the fixed cost is $0.01 * x = $0.01x

Now, the total cost on production which includes the fixed cost of the company would be $(0.01x + 60). This is the total amount spent to produce the goods.

Now revenue from sales for x toothpicks at $0.02 each is $0.02x

Since we are looking to Breakeven, we equate the costs to the revenue.

0.01x + 60 = 0.02x

0.02x-0.01x = 60

0.01x = 60

x = 60/0.01 = 6,000 toothpicks

6 0

3 years ago

The graph below shows the velocity f(t) of a runner during a certain time interval:

Snezhnost [94]

When graphs are plotted, graphs as in the .jpeg image in attachment are obtained.
First graph is line going through ordered pair (point) (0,6) and pair (6,8).
The second graph is line going through ordered pair (6,8) and pair (8,0).
Intercept of these graphs is point (ordered pair) (6,8).
You see from the .jpeg image that the following is true:
Initial velocity of the runner is 6 meters per second (runner starts with this velocity), for a while he runs, velocity grows, then in the 6th second (time=6), runner starts to slow down and velocity starts to decrease, and runner stops totally at time = 8.
So runner stops after 8 seconds.
The 4th claim (sentence) is correct.