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kirill [66]
3 years ago
10

what is the general equation of cosine function with a amplitude of 3 a period of 4pi and a horizontal shift of - pi

Mathematics
2 answers:
drek231 [11]3 years ago
5 0

Answer:

The answer is C

Step-by-step explanation:

I just took the test

kicyunya [14]3 years ago
4 0
The general form of such an equation will be
f(x)=A\cos\left(\dfrac{2\pi(x-B)}{C} \right)+D
where
  A = amplitude (3)
  B = horizontal shift to the right (-π)
  C = period (4π)
  D = vertical offset (0)

Your equation will be ...
f(x)=3\cos\left(\dfrac{x+\pi}{2}\right)

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Answer:

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Step-by-step explanation:

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Answer:

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