what is the general equation of cosine function with a amplitude of 3 a period of 4pi and a horizontal shift of - pi

Mathematics

2 answers:

drek231 [11]2 years ago

5 0

Answer:

The answer is C

Step-by-step explanation:

I just took the test

kicyunya [14]2 years ago

4 0

The general form of such an equation will be
$f(x)=A\cos\left(\dfrac{2\pi(x-B)}{C} \right)+D$
where
A = amplitude (3)
B = horizontal shift to the right (-π)
C = period (4π)
D = vertical offset (0)

Your equation will be ...
$f(x)=3\cos\left(\dfrac{x+\pi}{2}\right)$

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frez [133]

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Step-by-step explanation:

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2 years ago

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mel-nik [20]

Answer:

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Hope this helps :)

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2 years ago

Read 2 more answers

Help me please please

snow_lady [41]

Answer:

Step-by-step explanation:

Number 2 first:

See the graph below for a hint. (Do you know how to use Desmos ?)

factoring seems to make no sense for $y =-x^{2} +2x +4$ but "guess and check" seems to work. I tried 4 for x, but that proved false. 3 for x made sense. You get $-3x^{2} +2(3) +4 =y$ so -9 +6 +4 = 1 is true. So (3,1)