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3 years ago

Create medical term from the definition below. The word root has been provided for you. Stone in the bladder (Bladder: cyst/o)

Mathematics

1 answer:

adell [148]3 years ago

8 0

Answer:

Cystolith

Step-by-step explanation:

Etymology is the study of the history of the words, the origin of them. In medical terminology roots, suffices and prefixes in Latin and ancient greek are commonly used to describe symptoms, deceases, etc.

Prefixes don't require further modification to be added to a word root because the prefix normally ends in a vowel or vowel sound, suffixes are attached to the end of a word root to add meaning such as condition, disease process, or procedure.

Considering this we look for the Latin of stones, "lithus", and then modify it as a termination "-lite", -lith, and finally, we unify both words into one:

Cystolith

I hope you find this information useful and interesting! Good luck!

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2 years ago

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Solution:

Given that line is:

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The equation of line in slope intercept form is given as:

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We know that,

Product of slope of a line and slope of line perpendicular to given is always -1

Therefore,

$7 \times \text{ slope of line perpendicular to it } = -1\\\\\text{ slope of line perpendicular to it } = \frac{-1}{7}$

Now find the equation of line:

$\text{ Substitute } m = \frac{-1}{7} \text{ and } (x, y) = (6, -2) \text{ in eqn 1}$

$-2 = \frac{-1}{7} \times 6 + b\\\\-2 = \frac{-6}{7} + b\\\\b = -2+\frac{6}{7}\\\\b = \frac{-14+6}{7}\\\\b = \frac{-8}{7}$

$\text{Substitute } m = \frac{-1}{7} \text{ and } b = \frac{-8}{7} \text{ in eqn 1}\\\\y = \frac{-1}{7}x -\frac{8}{7}$

Thus the equation of line perpendicular to given line is found

<h3>Find the equation of the line that is parallel to this line and passes through the point (6, -2)</h3>

Slopes of parallel lines are equal

Therefore, m = 7

Substitute m = 7 and (x, y) = (6, -2) in eqn 1

-2 = 7(6) + b

-2 = 42 + b

b = -44

Substitute m = 7 and b = -44 in eqn 1

y = 7x - 44

Thus equation of line parallel to given line is found

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Answer:

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