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mario62 [17]
3 years ago
11

WILL GIVE BRAINLIEST!! PLEASE HELP ASAP!! PLEASE DON'T GUESS!! PLEASE GIVE THE DIRECT ANSWER!!

Mathematics
1 answer:
zaharov [31]3 years ago
7 0
Just saw the other answer XD You can delete this answer because it wrong. My mistake.
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.Jim opened an account with $400. The account pays three percent quarterly. How much is in the account at the end of two years?
podryga [215]
We may have this planned like this:
two years is 8 quarters 
<span>Assuming simple interest, </span>
You will use the formula
<span>A = P(1+rt) </span>
<span>= 400(1+8*.03) </span>
<span>= 496
</span>I think this is the answer:) Hope it helps a lot
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3 years ago
Help picture below problem 15
nikitadnepr [17]

Answer:

Supplementary

Step-by-step explanation:

The two angles are completely different from each other and if you combine them together it'll form a straight line making it 180 degrees

3 0
2 years ago
Round 715 to the nearest the ten
Mariana [72]
Here's a good rhyming rule to keep in mind.

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8 0
3 years ago
Read 2 more answers
Joe spent 1 1/3 hours studying for his math test. Randy studied for the amount of time that Joe did. What fraction of a hour did
PSYCHO15rus [73]

Answer:

1 1/3

Step-by-step explanation:

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7 0
3 years ago
GCSE 995381
nikdorinn [45]

Answer:

2.9 cm^2

Step-by-step explanation:

Given,

Angle of sector = 30°

Radius of circle, r = 8 cm

Area of the shaded region, A =?

The diagram is attached below.

Now,

Area of shaded region = Area of sector - Area of triangle

Area of triangle = \frac{1}{2}\times base \times height

We know that,

\sin \theta = \dfrac{P}{H}

\sin 30^\circ= \dfrac{P}{8}

P = \dfrac{8}{2}

P = 4\ cm

And

\cos \theta =\dfrac{B}{H}

\cos 30^\circ = \dfrac{B}{8}

B = \dfrac{8\times \sqrt{3}}{2}

B = 4\sqrt 3

Area of sector = \dfrac{\theta}{360^\circ}\times \pi r^2

Area of sector =  \dfrac{30^\circ}{360^\circ}\times \pi \times 8^2

                        = 16.75 cm^2

Area of triangle = \dfrac{1}{2} \times 4\sqrt 3 \times 4

                          = 13.85 cm^2

Area of shaded region = 16.75 - 13.85

                                      = 2.9 cm^2

7 0
2 years ago
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