All categories

3 years ago

6 (r - 4) + r + 30 - 7r

1 answer:

8 0

6r-24+r+30-7r (the we divide the regular numbers on one side and the others on the other side)Like this:
(6r+r-7r)+(-24+30)
(7r-7r)+6
And the final answer is 6

You might be interested in

Answer the question please I'll give brainlyest

disa [49]

Answer:

125 miles

Step-by-step explanation:

Speed travelled every hour = 50 miles

Time travelled for - 2 1/2 hours = 2.5 hours

Distance = Speed * Time

50*2.5 = 125 miles

Hope this helps!

6 0

2 years ago

Read 2 more answers

The weight, in pounds, of a newborn baby t months after birth can be modeled by W. A graph of W is shown below. Write an equatio

Agata [3.3K]

the First we need to choose two points in the graph

(0,6)=(t1,w1)

(1,7)=(t2,w2)

the variables are t and w

then we can calculate the slope

$m=\frac{w2-w1}{t2-t1}=\frac{7-6}{1-0}=\frac{1}{1}=1$

the equation of W is

where

m=1 ---> slope

b=6 ---> y-intercept

$\begin{gathered} W=mt+b \\ W=1\cdot t+6 \\ W=t+6 \end{gathered}$

the answers are

W=t+6

slope of the function 1

the answer is the third option

5 0

11 months ago

There are 10 employees in a particular division of a company. Their salaries have a mean of 570,000, a median of $55,000,and a s

harkovskaia [24]

Answer:

a) $160,000

b) $55,000

c) $332264.804

Step-by-step explanation:

We are given that there are 10 employees in a particular division of a company and their salaries have a mean of $70,000, a median of $55,000, and a standard deviation of $20,000.

And also the largest number on the list is $100,000 but By accident, this number is changed to $1,000,000.

a) Value of mean after the change in value is given by;

Original Mean = $70,000

$\frac{\sum X}{n}$ = $70,000 ⇒ $\sum X$ = 70,000 * 10 = $700,000

New $\sum X$ after change = $700,000 - $100,000 + $1,000,000 = $1600000

Therefore, New mean = $\frac{1600000}{10}$ = $160,000 .

b) Median will not get affected as median is the middle most value in the data set and since $1,000,000 is considered to be an outlier so median remain unchanged at $55,000 .

c) Original Variance = $20000^{2}$ i.e. $20000^{2}$ = $\frac{\sum x^{2} - n*xbar }{n -1}$

Original $\sum x^{2}$ = ( $20000^{2}$ * (10-1)) + (10 * 70,000) = $3,600,700,000

New $\sum x^{2}$ = $3,600,700,000 - $100,000^{2} + 1,000,000^{2}$ = 9.936007 * $10^{11}$

New Variance = $\frac{new\sum x^{2} - n*new xbar }{n -1}$ = $\frac{9.936007 *10^{11} - 10*160000 }{10 -1}$ = 1.103999 * $10^{11}$ Therefore, standard deviation after change = $\sqrt{1.103999 * 10^{11} }$ = $332264.804 .