Question

How many gallons of pure water should be added to 10 gallons of a solution containing 15 % juice so that the remaining solution contains 5 % juice? Fill in the table: What is the amount of juice in the original solution? a=. What is the original amount of solution in gallons? b =. How much juice is added? c= . How much total solution is added? d=.

Answer 1

Answer:

Step-by-step explanation: on edg

A=1.5

B=10

C=0

D=C

Answer 2

Answer:

a. 1.5 gallon of juice in the solution

b. 10 gallon

c. None

d. 10 gallon

Solution:

Let us assume that the w gallons of pure water to be added

so the total solution will be $(10+w)$ gallon

The 10 gallon of solution contain $15\%$ of juice $= (10\times\frac{15}{100} )gallon = 1.5 gallon$

Now, $\frac{1.5}{10+w} = 0.05$

$1.5 = 0.05(10+w)$

$150 = 5(10+w)$

$150 = 50 + 5w$

$5w = 150 - 50$

$5w = 100$

$w = 20$

The total amount water will be added is 20 gallon .