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4 years ago

There are (713)3 ⋅ 70 strawberries in a field. What is the total number of strawberries in the field?

Mathematics

2 answers:

nirvana33 [79]4 years ago

7 0

The answer is 210 strawberries on the field.

Paraphin [41]4 years ago

4 0

713
x 3
= 2139
2 6
2139
x 7
= 14873

There are a total of 14,873 strawberries in the field.

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Please help me with this

Gnoma [55]

Given:

The equation is:

$3^x\times 9=3^{2n-1}$

To find:

The value of n in terms of x.

Solution:

We have,

$3^x\times 9=3^{2n-1}$

It can be written as

$3^x\times 3^2=3^{2n-1}$

$3^{x+2}=3^{2n-1}$ $[\because a^ma^n=a^{m+n}]$

On comparing the exponents, we get

$x+2=2n-1$

Add 1 on both sides.

$x+2+1=2n-1+1$

$x+3=2n$

Divide both sides by 2.

$\dfrac{x+3}{2}=n$

Therefore, the value of n is terms of x is $n=\dfrac{x+3}{2}$ .

7 0

3 years ago

The area of parallelogram JKLM is 87.5 square feet. Its base is 14 feet. what is the height of parallelogram JKLM in feet?

Anna11 [10]

The height of parallelogram JKLM is 6.25 square feet. This is because the formula for the area of a parallelogram is base x height. So, since we have the base (14 feet), you simply divide the area (87.5 square feet) by the base, and get the final height (6.25 square feet. HOPE THIS HELPS!!!

5 0

4 years ago

Sec squared 55 - tan squared 55

sergejj [24]

<u>Answer: </u>

sec squared 55 – tan squared 55 = 1

<u>Explanation:</u>

Given, sec square 55 – tan squared 55

We know that,

$\sec \Theta=\frac{\text {hypotenuse}}{\text {base}}$

And,

$\tan \theta=\frac{\text { perpendicular }}{\text { base }}$

where Ө is the angle

Substituting the values

$\left(\frac{\text {hypotenuse}}{\text {base}}\right)^{2}-\left(\frac{\text { perpendicular }}{\text {base}}\right)^{2}$

Solving,

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}$

According to Pythagoras theorem,

$\text { (hypotenuse) }^{2}-\text { (perpendicular) }^{2}=(\text { base })^{2}$

Putting this in the equation;

squared 55 - tan squared 55 =

$\frac{(\text {hypotenuse})^{2}-(\text {perpendicular})^{2}}{(\text {base}) *(\text {base})}=\frac{(\text {base})^{2}}{(\text {base}) *(\text {base})}=1$

Therefore, sec squared 55 – tan squared 55 = 1

6 0

3 years ago

Which of the following statements are true of the graph of the function f(x)= (x+5)(x-3).

alexandr1967 [171]

Answer:

4 is the correct answer

Step-by-step explanation:

y=(x+5)(x-3)

so x intercept means the value of x when y is zero

0=(x+5)(x-3)

x+5=0 so x=-5

x-3=0 so x=3

5 0

3 years ago

Mrs. Doka is preheating her oven's. The oven's temperature increase 1/4 degree fahrenheit every 3/4 second. what is the oven's h

m_a_m_a [10]

.33 degrees per second, or 1/3 degrees

7 0

4 years ago