Help! the picture is the problemmm
1 answer:
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Answer:
430 cm2
Step-by-step explanation:
The Lateral Surface Area of it is equal to:
Area of ABCD + Area of A'B'C'D' + Area of ABB'A' + Area of DCC'D' + Area of ADD'A' + Area of BCC'B'
As ABCDA'B'C'D' is a rectangle prism, so that:
+) Area of ABCD = Area of A'B'C'D'
+) Area of ABB'A' = Area of DCC'D'
+) Area of ADD'A' = Area of BCC'B'
=> Total lateral surface area = 2. Area ABCD + 2. Area ABB'A + 2. Area ADD'A
As ABCDA'B'C'D' is a rectangle prism, so that we have: ABCD, ABB'A', ADD'A' are rectangles.
The formula to calculate the area of rectangle is: Area = Length x Width
We have:
+) Area ABCD = AB x BC =11 x 10 = 110 cm2
+) Area ABB'A = AB x AA' = 11 x 5 = 55 cm2
+) Area ADD'A = AA' x A'D' = 5 x 10 = 50cm2
Total lateral surface area = 2. Area ABCD + 2. Area ABB'A + 2. Area ADD'A
= 2 x 110 + 2 x 55 + 2 x 50 = 430 cm2
