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kramer
3 years ago
7

How do I find the length of GJ?

Mathematics
1 answer:
wlad13 [49]3 years ago
5 0
6(X+6)= 12(5)
6x+36=60
6x=24
X=4
Now put 4 in X of GJ
GJ=10
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In a test, John was able to answer 15 correct out of 40 questions. Beth was able to answer 24 questions correctly out of 50. Mic
Helen [10]

Answer:

that is wrong beth has a better score

Step-by-step explanation:

14 out of 40 is 37.5%

and 24 out of 50 is 48%

4 0
2 years ago
Jamar is four times as old as Josh. In 20 years he will be twice as old as Josh. How old is Jamar?
Juliette [100K]
Simultaneous equations
Jamar=J
Josh=j
4J=j
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Then
4J=j
-4 (J)=-4(2j-20)
So
0=-7j+80
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5 0
2 years ago
Misha used a probability simulator to pull 3 colored marbles from a bag and flip a coin 50 times. The results are shown in the t
kotykmax [81]

To solve this problem, let us first remember that probability is:

Probability = number of successful events / number of total events

 

Now, let us first calculate the probability of getting a blue marble. There are 20 blue marbles out of 50 total marbles, therefore the probability is:

P (blue marble) = 20 / 50 = 0.4

 

Next, let us calculate for the probability of landing tails up. There are 22 tails success out of 50 times the coin was tossed, therefore the probability is:

P (tails) = 22 / 50 = 0.44

 

Finally, since we want to find the Probability of getting blue and Probability of landing tails, we multiply the two:

P (blue and tails) = 0.4 * 0.44

P (blue and tails) = 0.176               (ANSWER)

 

Now if the choices are in fraction:

P (blue and tails) = (20 / 50) (22 / 50) = 440 / 2500

8 0
3 years ago
Read 2 more answers
Helpppppopoppoppppppppp
notka56 [123]

Answer:

0.19

Step-by-step explanation:

i am not so sure but it's my opinion

8[14-(7+4×4)]

__________

1-121-1-8

8[14-[44]

_______

-120-1-8

8[-30]

_____

119-8

8-30

____

111

-22

___

111

✓ 0.19

don't blame me if it is wrong lol

6 0
2 years ago
oyce is trying to solve the equation y = x2 − 8x + 7 using the quadratic formula. She has made an error in one of the steps belo
Naddik [55]

You didn't attach anything, but this is how you should solve this equation: given an equation ax^2+bx+c=0 the solutions are

x_{1,2} = \dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

In your case, the values are a=1,\ b=-8,\ c=7. If you plug these values inside the solving formula, you have

x_{1,2} = \dfrac{8\pm\sqrt{64-4\cdot 1\cdot 7}}{2\cdot 1} = \dfrac{8\pm\sqrt{64-28}}{2} = \dfrac{8\pm\sqrt{36}}{2} = \dfrac{8\pm6}{2} = 4\pm3

So, the two solutions are 1 and 7

3 0
3 years ago
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