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3 years ago

PLEASE HELP ME WITH THE QUESTION BELOW

Mathematics

1 answer:

Rom4ik [11]3 years ago

7 0

Answer:

C: (-5, 1)

Step-by-step explanation:

If you put the equation in a graphing calculator and examine all the points, C is the only one not on the line.

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Angles X and Y form a straight line. Angles W and Z form a straight line. Angles X and W are beside each other. Angles Y and Z a

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3 years ago

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For each of the following vector fields F, decide whether it is conservative or not by computing curl F. Type in a potential fun

Burka [1]

Answer:

1,2 and 4 are conservatives

3 is not conservative

Step-by-step explanation:

We calculate the Curl F

Remember that:

Curl F = < $\frac{dFz}{dy} - \frac{dFy}{dz}, \frac{dFz}{dx} - \frac{dFx}{dz}, \frac{dFy}{dx} - \frac{dFx}{dy}$ >

1. Curl F = <0,0,5-5> = <0,0,0>

The potential function f so that ∇f=F

f(x,y,z) = $-3x^{2} +5xy + 5y^{2}$

Then F is conservative

2. Curl F = < 0, 0 ,0>

The potential function f so that ∇f=F

f(x,y,z) = $-3/2x^{2} -y^{2}+z$

Then F is conservative

3. Curl F = <0 ,0, 10+3xsin(y) - (-cos(y))>

= <0 ,0 , 10 +3xsin(y) + cos(y)<

How the field's divergence is not zero the vector field is not conservative

4. Curl F = <0, 0, 0>

The potential function f so that ∇f=F

f(x,y,z) = $x^{3}+(5/3)y^{3}+(5/3)z^{3}$

Then F is conservative

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3 years ago

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must h

mestny [16]

Answer:

Radius =6.518 feet

Height = 26.074 feet

Step-by-step explanation:

The Volume of the Solid formed = Volume of the two Hemisphere + Volume of the Cylinder

Volume of a Hemisphere $=\frac{2}{3}\pi r^3$

Volume of a Cylinder $=\pi r^2 h$

Therefore:

The Volume of the Solid formed

$=2(\frac{2}{3}\pi r^3)+\pi r^2 h\\\frac{4}{3}\pi r^3+\pi r^2 h=4640\\\pi r^2(\frac{4r}{3}+ h)=4640\\\frac{4r}{3}+ h =\frac{4640}{\pi r^2} \\h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Area of the Hemisphere = $2\pi r^2$

Curved Surface Area of the Cylinder = $2\pi rh$

Total Surface Area=

$2\pi r^2+2\pi r^2+2\pi rh\\=4\pi r^2+2\pi rh$

Cost of the Hemispherical Ends = 2 X Cost of the surface area of the sides.

Therefore total Cost, C

$=2(4\pi r^2)+2\pi rh\\C=8\pi r^2+2\pi rh$

Recall: $h=\frac{4640}{\pi r^2}-\frac{4r}{3}$

Therefore:

$C=8\pi r^2+2\pi r(\frac{4640}{\pi r^2}-\frac{4r}{3})\\C=8\pi r^2+\frac{9280}{r}-\frac{8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{24\pi r^2-8\pi r^2}{3}\\C=\frac{9280}{r}+\frac{16\pi r^2}{3}\\C=\frac{27840+16\pi r^3}{3r}$