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gizmo_the_mogwai [7]
3 years ago
12

Anybody can I know is this the working and the answer are right? If any wrong plssss tell me.. ​

Mathematics
1 answer:
Alex3 years ago
7 0

Answer:

\boxed{Domain = \{3,6,9\}}

\boxed{Range = \{9,18\}}

Step-by-step explanation:

The relation is:

=> {(3,9)(3,18)(6,18)(9,18)}

Domain => x inputs of the ordered pair

Domain = {3,6,9}

Range => y inputs of the ordered pair

Range = {9,18}

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NEED HELP FAST I WILL MARK BRAINLYEST
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Answer:

13/48

Step-by-step explanation:

13/6 / 8 = 13/6 x 1/8

13 x 1 = 13

6 x 8 = 48

13/48

7 0
3 years ago
Read 2 more answers
What number must be added to both sides of the equation to complete the square?
adelina 88 [10]
(x-8)²= x²-16x+64
x²-16x+8=0
Therefore 56 must be added.

Good luck
7 0
3 years ago
• Since January 1980, the population, P, of the city of Brownville has increased closely modeling the
igomit [66]

Answer:

B) The population is increasing by 102.2% each year.

A) 720,500 represents the initial amount of people in January 1980 and 1.022 represents the increase factor that multiplies to the amount.

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6 0
3 years ago
A man invests a total of $9,493in two savings accounts. One account yields 9% simple interest and the other 10% simple interest.
Tju [1.3M]

$ 1850 was invested in 9% account

<u>Solution:</u>

Given that  

Total amount invested by man in two saving accounts = $9493

Simple interest on one account =9%

Simple interest on second account = 10%

Total interest earned = $930.80

Need to determine amount invested in 9 % account.

Let assume amount invested in account where Simple Interest is 9% = x

And assume amount invested in account where Simple Interest is 10% = y

As total amount invested in two accounts is $9493

=> x + y = 9493      

=> y = 9493 - x                              ------(1)

\text { Simple Interest }=\frac{\text { Amount Invested } \times \text {rate of interest } \times \text {time}}{100}

\begin{array}{l}{\text { Simple interest when rate of interest is } 9 \%=\frac{x \times 9 \times 1}{100}=\frac{9 x}{100}} \\\\ {\text { Simple interest when rate of interest is } 10 \%=\frac{y \times 10 \times 1}{100}=\frac{10 y}{100}}\end{array}

As total interest earned = $930.80

\begin{array}{l}{\Rightarrow \frac{9 x}{100}+\frac{10 y}{100}=930.80} \\\\ {\Rightarrow 9 x+10 y=930.80 \times 100} \\\\ {\Rightarrow 9 x+10 y=93080}\end{array}

On substituting value of y from equation(1) in above equation , we get

9x + 10 (9493 – x) = 93080

=> 9x  + 94930 – 10x = 93080

=> -x = 93080 – 94930

=> -x = -1850

=> x = 1850  

Amount invested in account where Simple Interest is 9% = x  = $1850

Hence $1850 was invested in 9% account.

5 0
3 years ago
Chloe was x inches tall on her birthday last year. This year she is 2.5 inches taller. Select all of the following expressions t
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X+2.5 because you dont know her height of last year which would give you the variable X and this year she grew 2.5 inches which would make the equation X+2.5 
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