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sashaice [31]
3 years ago
13

Find the simple interest on £120,000.00 for 5 months at 12% per annum​

Mathematics
1 answer:
Vinil7 [7]3 years ago
3 0

Answer:

£6,000

Step-by-step explanation:

<u>Use the simple interest formula:</u>

I = Prt

I = (Principal Value)*(Annual Interest Rate)*(Time in Years)

I = (120000)(0.12)(5/12)

I = 6000

Therefore, the simple interest is £6,000

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the lines are below are parallel . if the slope of the green line is - 2/3 , what is the slope of the red line?
lina2011 [118]
If the two lines a re parallel, they would have the same slop which means the red line would have a slope of - 2/3
3 0
3 years ago
The radius of the base of a cylinder is 27 cm and its height is 37 cm. Find the surface area of the cylinder in terms of π
Nonamiya [84]
Surface area of a cylinder = 2 x Pi x r^2 + 2 x Pi x r x h

R = 27 cm
H = 37 cm

Take away the Pi seeing as you want to keep it in terms of Pi

2 x 27^2 + 2 x 27 x 37 = 3456 Pi cm^2
Your answer is B
7 0
3 years ago
Read 2 more answers
Simplify -4x + 3y + -2z + 2y
Katarina [22]

Answer:

−4+5−2

Step-by-step explanation:

Just combine the like terms which are 3y and 2y, you add and get 5y and everything else stays the same

6 0
2 years ago
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Given the isosceles trapezoid below, find AG.<br> Show all the work
Dmitry [639]

We know the width of the rectangle in the middle of the trapezoid is 24 (from the top of the image), so we can subtract that from the bottom width of the trapezoid to get the combined length of the bottom of both triangles.

40 - 24 = 16

Since this is an isosceles trapezoid, both triangle bases are the same length, so we can cut this value in half to get the length of GT and EF

\frac{16}{2} = 8

Finally, we can use the Pythagorean Theorem to find the length of AG:

AG^{2} + GT^{2} = AT^{2}

AG^{2} + 8^{2} = 10^{2}

AG^{2} + 64 = 100

AG^{2} = 36

AG = 6

8 0
2 years ago
Which operation can be used with the augmented matrix below?
ycow [4]

Answer:

Multiply row 2 by-1 and add it to row 3.

Step-by-step explanation:

The given augmented matrix is \left[\begin{array}{ccc}3&-21&15\\15&8&15\\-2&-1&3\end{array}\right]

The permissible row operations are:

1. Switching rows

2. Multiplying a row by a nonzero constant.

3. Adding/Subtracting two rows

 Therefore the correct option is: Multiply row 2 by-1 and add it to row 3.

5 0
4 years ago
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