Answer:
I think it's C, I may be wrong though
Step-by-step explanation:
Answer:
<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>
Step-by-step explanation:
We know

for any real value of <em>a</em>.
|a| = b > 0 - <em>two solutions: </em>a = b or a = -b
|a| = 0 - <em>one solution: a = 0</em>
|a| = b < 0 - <em>no solution</em>
<em />
|x + 6| - 4 = c
for c = 5:
|x + 6| - 4 = 5 <em>add 4 to both sides</em>
|x + 6| = 9 > 0 <em>TWO SOLUTIONS</em>
for c = -10
|x + 6| - 4 = -10 <em>add 4 to both sides</em>
|x + 6| = -6 < 0 <em>NO SOLUTIONS</em>
<em></em>
Calculate the solutions for c = 5:
|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9 <em>subtract 6 from both sides</em>
x = 3 or x = -15
Answer:
3 with a few left over so 4
Step-by-step explanation:
Answer:
x = 16
Step-by-step explanation:
5 = 1/2(x) - 3
Add 3 to both sides.
8 = 1/2(x)
Rewrite for clarity.
1/2(x) = 8
x/2 = 8
Multiply both sides by 2.
x = 16.
Proof:
5 = 1/2(x) - 3
Substitute variable.
5 = 1/2(16) - 3
Multiply 1/2 and 16.
5 = 8 - 3
Subtract 3 from 8.
5 = 5
The answer is A. He can only work 2 more days with 8 hours a day