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Lerok [7]
3 years ago
13

Pls help me tysm if you can!!

Mathematics
2 answers:
Mice21 [21]3 years ago
8 0
The answer is 0.687.
NeTakaya3 years ago
3 0
<h2><u>Answer is 0.687.</u></h2>

Since you're dividing by 100, simply move the decimal point to the left twice.

68.7 will now become 0.687.

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(x³)² × x⁴ = ?<br>(it won't lemme type short)​
Alex73 [517]

Answer:

We have x^3^2 which is x^3*2 = x*6 times x*4 which is x*10

Hope this helped and brainliest please

4 0
2 years ago
7 and 14 and 49 lcm for the mathematics
Deffense [45]
The answer would be 98
8 0
3 years ago
A consumer organization inspecting new cars found that many had appearance defects (dents, scratches, paint chips, etc.). While
Murljashka [212]

Answer:

The expected number of appearance defects in a new car  = 0.64

standard deviation = 0.93(approximately)

Step-by-step explanation:

Given -

7% had exactly three, 11% exactly two, and 21% only one defect in cars.

Let X be no of defects in a car

P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21

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The expected number of appearance defects in a new car =

E(X) = \nu = = \sum X P(X) =3\times 0.07 + 2\times0.11 + 3\times0.21 + 0\times0.61 = 0.64

\sigma^{2}  = variation of E(X) = \sum (X - \nu) ^{2}P(X) = (3 - 0.64) ^{2}\times0.07 + (2 - 0.64) ^{2}\times0.11 + (1 - 0.64) ^{2}\times0.21 + (0 - 0.64) ^{2}\times0.61

 = (2.36) ^{2}\times0.07 + (1.36) ^{2}\times0.11 + (.36) ^{2}\times0.21 + ( 0.64) ^{2}\times0.61 = 0.8704

standard deviation  =  \sqrt{\sigma^{2}} = \sqrt{0.8704^{2}} = 0.93(approximately)

4 0
3 years ago
A car company said that its top five models had the following fuel efficiency ratings: 26.3 mpg, 28.95 mpg, 33.6 mpg, 35 mpg, 38
MissTica
32.148 is the exact average.
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3 years ago
Golf course designer Roberto Langabeer is evaluating two sites, Palmetto Dunes and Ocean Greens, for his next golf course. He wa
Scilla [17]

Answer

The answer and procedures of the exercise are attached in the following archives.

Step-by-step explanation:

You will find the procedures, formulas or necessary explanations in the archive attached below. If you have any question ask and I will aclare your doubts kindly.  

3 0
3 years ago
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