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stira [4]
3 years ago
5

Calculating Distance around a Polygon

Mathematics
1 answer:
RideAnS [48]3 years ago
3 0

Answer:

12.5cm

Step-by-step explanation:

Each side of the pentagonal  garden has a length of 2.5 cm.

A pentagon has 5 sides.

Since the garden has congruent sides, all its lengths are equal.

Therefore:

Distance Walked by Tanya

= 5 X 2.5

=12.5cm

Tanya has walked 12.5cm in total.

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Precalculus. Please look at the picture
erik [133]

Answer:

<u>Exponential model</u>

y=Ae^{rt}

where:

  • y = value at "t" time
  • A = initial value
  • r = rate of growth/decay
  • t = time (in years)

<h3><u>Part (a)</u></h3>

Given:

  • y = 100 g
  • t = 0 years

Substituting given values into the formula and solving for A:

\begin{aligned}y & =Ae^{rt}\\\implies 100 & = Ae^{r \times 0}\\100 & = Ae^0\\100 & = A(1)\\A & = 100\end{aligned}

<h3><u>Part (b)</u></h3>

Given:

  • A = 100 g
  • y = 50 g when t = 30.17

Substituting the given values into the equation and solving for r:

\begin{aligned}y& =Ae^{rt}\\\\\implies 50 & =100e^{30.17r}\\\\\dfrac{1}{2} & = e^{30.17r}\\\\ln \dfrac{1}{2} & = \ln e^{30.17r}\\\\\ln 1-\ln2 & =30.17r \ln e\\\\0-\ln 2 & =30.17r(1)\\\\-\ln 2 & =30.17r\\\\r & = \dfrac{-\ln 2}{30.17}\end{aligned}

Therefore, the final equation is:

y=100e^{\left(-\dfrac{\ln 2}{30.17}\right)t}

<h3><u>Question 1</u></h3>

<u>Part (a)</u>

Q:   From 100g how much remains in 80 years?

\begin{aligned}t=80 \implies y & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)80}\\& = 15.91389949 \: \sf g\end{aligned}

<u>Part (b)</u>

Q:  How long will it take to have 10% remaining?

10% of 100 g = 10 g

\begin{aligned}y=10 \implies 10 & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\dfrac{1}{10} & =e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln \dfrac{1}{10} & =\ln e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln 1 - \ln 10 & =\left(-\dfrac{\ln 2}{30.17}\right)t\ln e\\\\0 - \ln 10 & =\left(-\dfrac{\ln 2}{30.17}\right)t(1)\\\\-\ln 10 & =\left(-\dfrac{\ln 2}{30.17}\right)t\\\\t & = \dfrac{- \ln 10}{\left(-\dfrac{\ln 2}{30.17}\right)}\\\\t & = 100.2225706\: \sf years\end{aligned}

<h3><u>Question 2</u></h3>

<u>Part (a)</u>

Q:   How much remains after 50 years (time)?

<u></u>

\begin{aligned}t=50 \implies y & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)50}\\& = 31.70373153 \: \sf g\end{aligned}

<u>Part (b)</u>

Q:   How long to reach 20 g (amount remaining)?

<u></u>\begin{aligned}y=20 \implies 20 & =100e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\dfrac{1}{5} & =e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln \dfrac{1}{5} & =\ln e^{\left(-\dfrac{\ln 2}{30.17}\right)t}\\\\\ln 1 - \ln 5 & =\left(-\dfrac{\ln 2}{30.17}\right)t\ln e\\\\0 - \ln 5 & =\left(-\dfrac{\ln 2}{30.17}\right)t(1)\\\\-\ln 5 & =\left(-\dfrac{\ln 2}{30.17}\right)t\\\\t & = \dfrac{- \ln 5}{\left(-\dfrac{\ln 2}{30.17}\right)}\\\\t & = 70.05257062\: \sf years\end{aligned}

3 0
2 years ago
Kim was walking down a rocky path. For 4 minutes, the elevation dropped at the same rate. Altogether it dropped 8 feet. What was
Marianna [84]

Answer:

-2 ft/min

Step-by-step explanation:

If Kim dropped for a total of 8 feet over the course of 4 minutes, then 8 feet/4 min equals 2 ft/min, but because they are dropping it should be negative.

7 0
3 years ago
Find f(x) and g(x) so the function can be expressed as y = f(g(x)). y = Two divided by x squared. + 3
kodGreya [7K]
Hello,

g(x)=x²+3
f(x)=2/x
so f(g(x))=f(x²+3)=2/(x²+3)

Explainations:

f(y)=2/y
f(4y)=2/(4y)
f(x²)=2/x²
f(x²+3)=2/(x²+3)

4 0
4 years ago
Simplify the answer 21/10+5/10
Softa [21]
21/10+5/10
Add nominators since denominators are the same.
26/10
Or 2 6/10 as a mixed number.
3 0
3 years ago
What is the product?
Juli2301 [7.4K]
Your answer should be C or the third one

3 0
4 years ago
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