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3 years ago

For number 28 you need to use point-slope form, which is y-y1=m(x-x1), through the points (4, 2) and (-2, 5)

Mathematics

1 answer:

Illusion [34]3 years ago

8 0

28) Slope is (5-2)/(-2-4) = 3/-6 = -1/2 so a possible point-slope form is

y - 2 = -1/2(x-4)

29) y = -2 is a horizontal line. If you are wanting a line perp. to a horizontal line, you get a vertical line of the form x = a. Since it passes through (-2,-1), the point slope form is just x = -2 (there's no real point slope form because there is no y. vertical line does not care about y; all the y-values are on the vertical line)

30) Since 25*3 = 75, √(75) = √(25*3)=√25 * √3 = 5√3

31) √128 = √(64 * 2) = 8√2

32) √144 = 12 because 12*12 = 144

33) 4√(54) = 4√(9*6) = 12√6

34) 2√(32) = 2√(16*2) = 8√2

35) -6√175 = -6√(25*7) = -30√7

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Need help please, does any one know how to do this

ziro4ka [17]

Answer:

(6-u)/(2+u)
8/(u+2) -1
-u/(u+2) +6/(u+2)

Step-by-step explanation:

There are a few ways you can write the equivalent of this.

1) Distribute the minus sign. The starting numerator is -(u-6). After you distribute the minus sign, you get -u+6. You can leave it like that, so that your equivalent form is ...

(-u+6)/(u+2)

Or, you can rearrange the terms so the leading coefficient is positive:

(6 -u)/(u +2)

2) You can perform the division and express the result as a quotient and a remainder. Once again, you can choose to make the leading coefficient positive or not.

-(u -6)/(u +2) = (-(u +2)-8)/(u +2) = -(u+2)/(u+2) +8/(u+2) = -1 + 8/(u+2)

8/(u+2) -1

Of course, anywhere along the chain of equal signs the expressions are equivalent.

3) You can separate the numerator terms, expressing each over the denominator:

(-u +6)/(u+2) = -u/(u+2) +6/(u+2)

4) You can also multiply numerator and denominator by some constant, say 3:

-(3u -18)/(3u +6)

You could do the same thing with a variable, as long as you restrict the variable to be non-zero. Or, you could use a non-zero expression, such as 1+x^2:

(1+x^2)(6 -u)/((1+x^2)(u+2))

7 0

3 years ago

What is the sum of the measures of the exterior angles of a decagon?

My name is Ann [436]

Answer:

360°

Step-by-step explanation:

The sum of the exterior angles of any polygon is 360°

sum of exterior angles of decagon = 360°

4 0

2 years ago

Find the measure of each minor arc formed by a regular octagon inscribed in a circle. A. 15° B. 30° C.45° D. 60°

marin [14]

Your octagon has a central angle of 360 deg. Since you're speaking of an octagon, which implies that the octagon is made up of eight triangles, divide 360 deg by 8 to obtain the measure of each minor arc formed.

6 0

3 years ago

The perimeter of this Hexagon is 162 cm. Each longer side measures 1 cm more than twice a shorter side. Find the length of the l

Elis [28]

Let x represent the shorter sides, then 2x + 1 would represent the longer sides. There are four short sides and two long sides. The perimeter is 162 cm. The equation: 4x + 2(2x + 1) = 162 4x + 8x + 2 = 162 8x + 2 = 162 Subtract 2 from both sides. 8x = 160 Divide both sides by 8. x = 20 The shorter sides are 20 cm in length. The longer sides are 2x + 1, or 41 cm in length. Check: 4 * 20 + 2 * 41 = 162 80 + 82 = 162 162 = 162, values check.

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3 years ago

If the perimeter of this triangle is to be no more than 77 feet, write an inequality and

Sergio039 [100]

Given:

Consider the sides of the triangle are 4x+10, 2x-5 and 18 (in feet).

Perimeter of this triangle is to be no more than 77 feet.

To find:

The inequality and solution of the inequality.

Solution:

Perimeter of a triangle is the sum of all side.

Perimeter of given triangle $=(4x+10)+(2x-5)+18$