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Nataly [62]
3 years ago
8

A test is worth 50 points. Multiple- choice questions are worth 1 point, and short answer questions are worth 3 points. if the t

est has 20 questions, how many multiple-choice questions are there?
A. s for short answer, t for test

B. m for multiple choice, s for short answer

C. t for test, q for questions

D. p for points, m for multiple choice
Mathematics
2 answers:
DedPeter [7]3 years ago
5 0

Answer:

15 Short Answer Questions

( =45 points)

Step-by-step explanation:

STatiana [176]3 years ago
4 0
15 Short Answer Questions
( =45 points)

5 Multiple Choice Questions
( = 5 points)
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158÷37 show work need help
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Here’s a pic of my work, it shows that the numbers 2,7,0 repeat.

Hope this helps!! :)
8 0
3 years ago
Paige measured 4/9 cup of onions, 3/4 cup of celery, and 2/7 cup of carrots. How many cups of vegetables did Paige measure out f
lozanna [386]
1whole 121/252
sorry if it's wrong
3 0
3 years ago
Read 2 more answers
Please someone help me to prove this. ​
morpeh [17]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities:   sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

<u />

<u>Proof LHS → RHS</u>

LHS:                                  2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle:    2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]  

Expand:        2[(1/2)cos²2A  + cos2A·sin2A + (1/2)sin²2A]

Distribute:              cos²2A   + 2cos2A·sin2A + sin²2A  

Pythagorean Identity:    1 + 2cos2A·sin2A

Double Angle:                1 + sin4A

LHS = RHS:  1 + sin4A = 1 + sin4A   \checkmark

6 0
3 years ago
Which value of HNK are used to write the function f(x) = x2 + 12x + 6 in vertex form?
anygoal [31]

Answer:

( − 6 , − 30 )

Step-by-step explanation:

Rewrite in vertex form and use this form to find the vertex  ( h , k ) .

6 0
3 years ago
The amount of polonium-210 remaining, p(t), after t days in a sample can be modeled by the exponential function p(t) = 100e−0.00
Archy [21]

Answer:

% Po lost = 100[1 - e^(-0.005t)]  %; 73.0 g

Step-by-step explanation:

p(t) = 100e^(-0.005t)

Initial amount:        p(0) = 100

Amount remaining: p(t) = 100e^(-0.005t)

Amount lost: p(0) – p(t) = 100 - 100e^(-0.005t) = 100[1 - e^(-0.005t)]

% of Po lost  = amount lost/initial amount × 100 %

= [1 - e^(-0.005t)]  × 100 % = 100[1 - e^(-0.005t)]  %

p(63) = 100e^(-0.005 × 63) = 100e^(-0.315) = 100 × 0.730 = 73 g

The mass of polonium remaining after 63 days is 73 g.

4 0
3 years ago
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