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Andru [333]
3 years ago
15

Which of the following is most likely to own the data resulting from a research project?

Computers and Technology
1 answer:
fomenos3 years ago
4 0

Answer:

Option C i.e., ODS/Data warehouse is the correct answer.

Explanation:

The following option is correct because ODS/Data warehouse owns that resulting data from that project which is related to research. ODS transfer the data of the database to the data warehouses before processing that data or information in the database which is collected from the different-different sources

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Letter Frequency Write a function that will take a string and return a count of each letter in the string. For example, "my dog
Nostrana [21]

Answer:

Check the explanation

Explanation:

Code to copy:

// ConsoleApplication7.cpp : Defines the entry point for the console application.

//

#include "stdafx.h"

#include <iostream>

#include <cstring>

#include <string>

using namespace std;

int * letterFrequency(char s[]);

int main()

{

  int *freq_letters;

  char *s = new char[100];

  freq_letters = new int[26];

  //To read the input string in order to find the frequency of each letter

  cout << "Enter a string: ";

  cin.getline(s, ' ');

  //call the function to find the occurrence of each alphabet

  freq_letters = letterFrequency(s);

  //Display the count

  cout << "Letter Frequency " << endl;

  for (int i = 0; i < 26; i++)

  {

      //Constriant to check if the letter appeared at least once in the string and so printing the frequency of its occurence

      if (freq_letters[i] != 0)

      cout << " " << static_cast<char>(i + 'a') << " " << freq_letters[i] << endl;

  }

  system("pause");

  return 0;

}

//Define the function to find occurrence of each letter in the input string

int * letterFrequency(char s[])

{

  int *occurrence_array;

//to store the output of occurrences for each alphabet

  occurrence_array = new int[26];

// to store the count of occurrence for each letter temporarily

  int letter_count;

  // for loop to check the occurrence for all 26 alphabets

 

  for (int i = 0; i < 26; i++)

  {

      letter_count = 0;

      for (int j = 0; j < strlen(s); j++)

      {

          /*comparing the ascii values of each alphabet with every character from the string by converting it to lower case i.e. case insensitive*/

          if (int('a') + i == int(tolower(s[j])))

              letter_count++;

      }

      occurrence_array[i] = letter_count;//To store the count calculated for each alphabet

  }

  return occurrence_array;

}

The following below code screenshot and output shows that when the string is entered, the output will shows each lettercount irrespective of whether the letter is in capitals or small and does not count non-letter characters (i.e spaces, punctuations etc.)

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Answer
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What does the Autosum feature on excel do?
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Explanation:

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