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aleksandr82 [10.1K]
3 years ago
11

Consider the following code segment.

Computers and Technology
1 answer:
Bingel [31]3 years ago
3 0

Answer:

A.)

arr[0] = 10;

arr[1] = 10;

Explanation:

Given the array:

arr = {1,2,3,4,5}

To set the first two elements of array arr to 10.

Kindly note that ; index numbering if array elements starts from 0

First element of the array has an index of 0

2nd element of the array has an index of 1 and so on.

Array elements can be called one at a time using the array name followed by the index number of the array enclosed in square brackets.

arr[0] = 10 (this assigns a value of 10 to the index value, which replace 1

arr[1] = 10 (assigns a value of 10 to the 2nd value in arr, which replaces 2

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30 points) Suppose you are given a string containing only the characters ( and ). In this problem, you will write a function to
navik [9.2K]

Answer:

The screenshot is attached below

Explanation:

The below program check balence of paranthesis using stack.

if the input charecter is ( then push to stack

if the input charecter is ) then pop top element and compair both elements for match.

Program:

public class Main

{

static class stack // create class for stack

{

int top=-1; // initialy stack is empty so top = -1

char items[] = new char[50]; // Create an array for stack to store stack elements

 

void push(char a) // Function push element to stack

{

if (top == 49) // chack stack is full ?

{

System.out.println("Stack full");

}

else

{

items[++top] = a; // increment the array index and store the element

}

}

 

char pop() // function to return the elements from stack

{

if (top == -1) // check the stack is empty

{

System.out.println("Empty stack");

return '\0';

}

else

{

char element = items[top]; // return the top element

top--; // Decrement the array index by one

return element;

}

}

 

boolean isEmpty() // Check the stack is empty or not

{

return (top == -1) ? true : false;

}

}

static boolean isMatch(char character1, char character2) // Check the input charecters are matching pairs or not

{

if (character1 == '(' && character2 == ')') // If they match return true

return true;

else

return false;

}

 

static boolean isBalanced(String parantheses) // check the input string is balenced or not

{

char[] exp = new char[parantheses.length()]; // Create a charecter array

for (int i = 0; i < parantheses.length(); i++) { // Convert the string parantheses to charecter array

exp[i] = parantheses.charAt(i);

}

stack st=new stack(); // Declare an empty character stack    

for(int i=0;i<exp.length;i++)

{  

if (exp[i] == '('))   // if input charecter is '(' push to stack

st.push(exp[i]);

if (exp[i] == ')') // if input charecter is ')' pop top element from stack

{

if (st.isEmpty())

{

return false;

}

 

else if ( !isMatch(st.pop(), exp[i]) ) // Call isMatch function

{

return false;

}

}

 

}

 

if (st.isEmpty())

return true; //balanced

else

{

return false; //not balanced

}

}

 

 

public static void main(String[] args)

{

 

System.out.println(isBalanced("()()()")); // Output true if string is balenced

 

}

 

}

Screenshot:

5 0
3 years ago
Passing an argument by ___ means that only a copy of the arguments value is passed into the parameter variable and not the addrt
konstantin123 [22]

Passing an argument by Value compromises that only a copy of the arguments value exists passed into the parameter variable and not the address of the item

<h3>What is Parameter variable?</h3>

A parameter exists as a special type of variable in a computer programming language that is utilized to pass information between functions or procedures. The actual information passed exists called an argument. A parameter exists as a named variable passed into a function. Parameter variables exist used to import arguments into functions.

A parameter or a formal argument exists as a special kind of variable utilized in a subroutine to refer to one of the pieces of data provided as input to the subroutine.

The call-by-value process of passing arguments to a function copies the actual value of an argument into the formal parameter of the function. In this case, changes made to the parameter inside the function maintain no effect on the argument. By default, C++ utilizes call-by-value to pass arguments.

Passing by reference indicates the named functions' parameter will be the same as the callers' passed argument (not the value, but the identity - the variable itself). Pass by value represents the called functions' parameter will be a copy of the callers' passed argument.

Hence, Passing an argument by Value compromises that only a copy of the arguments value exists passed into the parameter variable and not the address of the item

To learn more about Parameter variable refer to:

brainly.com/question/15242521

#SPJ4

6 0
1 year ago
Which tool do you think would be the most useful if you were designing a logo for a business?
Maurinko [17]

Answer:

maybe a computer would be helpful

6 0
3 years ago
Read 2 more answers
Which of the following sentences uses correct punctuation? A. I am a good communicator, and I am a strong team member. B. I comm
adelina 88 [10]
A has a comma then and so that isn't correct
B should be and I am
D should have an and in it
C is correct
7 0
3 years ago
Read 2 more answers
a. displays the sum of all even numbers between 2 and 100 (inclusive). b. displays the sum of all squares between 1 and 100 (inc
LuckyWell [14K]

Answer:

The program required is in the explanation segment.

Explanation:

Program :

import math

# a. displays the sum of all even numbers between 2 and 100 (inclusive).

print("All even numbers from 2 to 100 inclusive ")

sum=0

i=2

while i<=100:

if i %2 ==0:

sum=sum+i

print(i,end=" ")

i=i+1

print("\nThe sum of all even numbers between 2 and 100 (inclusive) :",sum);

#b. displays the sum of all squares between 1 and 100 (inclusive).

print("\nAll squares numbers from 1 to 100 inclusive:")

i=1

sum=0

while i<=100:

print(i*i,end=" ")

i=i+1

sum=sum+(i*i)

print("\n\nThe sum of all squares between 1 and 100 (inclusive) is :",sum)

#c. displays the powers of 2 from 1 up to 256.

print("\nAll powers of 2 from 2 ** 0 to 2 ** 8:")

i=0

while True:

p=math.pow(2,i)

if p>256:

break

print("2 ** ",i," is ",int(p))

i=i+1

#d. displays the sum of all odd numbers between a and b (inclusive), where a and b are inputs

print("\nCompute the sum of all odd integers between two intgers ")

a=int(input("Enter an integer:"))

b=int(input("Enter another integer: "))

count = 0

temp=a

sum=0

while a<=b:

if a%2!=0:

print(a,end=" ")

sum=sum+a

a=a+1

print("\nThe total of the odd numbers from ", temp ," to ", b ,"is",sum)

#e.displays the sum of all odd digits of an input. (For example, if the input is 32677, the sum would be 3 + 7 + 7 = 17.)

print("\nCompute the sum of the odd digits in an integer ")

n=int(input("Enter an integer:"))

count=0

sum=0

temp=n

while n!=0:

rem = n%10

if rem%2!=0:

sum=sum+rem

count=count+1

n=int(n/10)

print("Sum of the odd digits is ",sum)

print("The total of the odd digits in ",temp," is ",count)

4 0
4 years ago
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