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il63 [147K]
3 years ago
12

Sam drove 696 in 12 hours. At this same rate, how long would it take him to drive 464 miles?

Mathematics
2 answers:
MArishka [77]3 years ago
8 0
696/12 = 464/x

696x = 464 *12 ...cross multiply
696x = 5568
x = 5568/696
x=8

answer: <span>464 miles in 8 hours</span>
stiv31 [10]3 years ago
5 0
Sam took 8 hours to drive 464 miles
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MJN

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6 0
4 years ago
the class marks of a distribution are 37 42 and 47 the class limits corresponding to class mark 42 are
I am Lyosha [343]

Answer:

39.5,44.5

Step-by-step explanation:

Let\ the\ lower\ limit\ and\ the\ upper\ limit\ of\ the\ first\ interval\ be\ u_1,v_1.\\Let\ the\ lower\ limit\ and\ the\ upper\ limit\ of\ the\ second\ interval\ be\ u_2,v_2.\\Let\ the\ lower\ limit\ and\ the\ upper\ limit\ of\ the\ third\ interval\ be\ u_3,v_3.\\Hence,\\As\ the\ class\ marks\ are\ uniform\ with\ an\ a\ difference\ of\ 5, the\\ observation\ is\ continuous\ and\ the\ class\ size\ is\ 5\ too.\\Hence,\\v_1=u_2, v_2=u_3\\Now,\\Lets\ consider\ the\ first\ two\ classes.\\37=\frac{u_1+v_1}{2} \\42=\frac{u_2+v_2}{2}\\By\ adding\ the\ equations:\\79= \frac{u_1+v_1}{2}+\frac{u_2+v_2}{2}\\79=\frac{u_1+v_1+u_2+v_2}{2}\\79=\frac{(u_1+v_2)+(v_1+u_2)}{2}\\79=\frac{(u_1+v_2)}{2}+\frac{(v_1+u_2)}{2}\\Now,\\As\ the\ mid-point\ between\ two\ points\ can\ be\ calculated\ by\\ its\ average:\frac{u+v}{2} \\Hence,\\u_2\ lies\ in\ the\ mid-point\ of\ u_1\ and\ v_2.\\u_2=\frac{(u_1+v_2)}{2}\\

Hence,\\By\ substituting\ u_2=\frac{(u_1+v_2)}{2},\\79=u_2+\frac{v_1+u_2}{2}\\As\ v_1=u_2[Proven],\\79=u_2+ \frac{u_2+u_2}{2}\\79=u_2+\frac{2u_2}{2}\\79=2u_2\\Hence,\\u_2=\frac{79}{2}\\u_2=39.5\\Now,\ as\ we\ already\ know\ that\ the\ class\ size=5,\\v_2-u_2=5\\Hence,\\v_2=5+u_2\\Here,\\v_2=5+39.5\\v_2=44.5\\Hence,\\The\ upper\ limit\ of\ the\ second\ interval=44.5\\The\ lower\ limit\ of\ the\ second\ interval=39.5\\

7 0
3 years ago
H/j=15 solve for j <br> Please answer
Katyanochek1 [597]
Hey!

Let's write the problem,
\frac{H}{j}=15
Multiply both sides by j in order to undo the fraction.
\frac{H}{j}j=15j
H=15j
Let's switch sides so that we end up with j on the left side.
15j=H
Divide both sides by 15.
\frac{15j}{15}=\frac{H}{15}

Our final answer would be,
j=\frac{H}{15}

Thanks!
-TetraFish
5 0
3 years ago
I need help identifying if this is a 90,180,270 degree transformation
Arte-miy333 [17]
\begin{gathered} Choosing\text{ one point} \\ K(-1,-4) \\ K^{\prime}(1,4) \\ It\text{ means} \\ K^{\prime}=K(-x,-y) \\ Hence \\ This\text{ is a 180\degree transformation} \end{gathered}

6 0
1 year ago
Help? I don't get it. If you could show the process tha'd be great! :)
Vaselesa [24]
This is the input/output table for a linear function. Linear functions increase or decrease by a constant value (the slope).

(38 - 19) / (2 -1) = 19

See how every output is +19 the one before it?
then the output following 57 is 57+19 = 76
1 is one 19
2 is two 19's
3 is three 19's
n is 19n
3 0
3 years ago
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