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3 years ago

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rosy has 16 pencils and 24 erasers. she is putting together packets that will have an equal number of pencils and erasers in eac

h packet. If rosy uses all of the pencils and erasers, what’d the max number of packets she can make?

1 answer:

faust18 [17]3 years ago

4 0

Answer:48

Step-by-step explanation: you were indirectly asked for the L.C. M of 16 and 24

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Slove : 28/36 = 14/y

Dafna1 [17]

Answer:

y = 18

Step-by-step explanation:

<h3><u>i</u><u>)</u><u> </u><u>redu</u><u>ce</u><u> the</u><u> fraction</u><u> </u><u>with</u><u> </u><u>4</u></h3>

$\frac{28}{36} = \frac{14}{y}$

$\frac{28 \div 4}{36 \div 4} = \frac{14}{y}$

$\frac{7}{9} = \frac{14}{y}$

<h3><u>ii</u><u>)</u><u> </u><u>simpl</u><u>ify</u><u> the</u><u> </u><u>eq</u><u>uation</u><u> </u><u>with</u><u> </u><u>cross</u><u> </u><u>multiplication</u></h3>

$\frac{7}{9} = \frac{14}{y}$

$7y = 14 \times 9$

$7y = 126$

<h3>iii) <u>divi</u><u>de</u><u> both</u><u> sides</u><u> of</u><u> the</u><u> equation</u><u> </u><u>by</u><u> </u><u>7</u></h3>

<u> $\frac{7y}{7} = \frac{126}{7}$ </u>

<u> $y = 18$ </u>

7 0

3 years ago

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The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d

aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

<h3 /><h3>Step 1</h3>

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

$f(t)=\left \{ {{0 ,\-t$

Consider the second function:

$f(t)=\frac{e^{-t/\mu}}{\mu}\\$

Where Average waiting time = μ = 2.5

The function f(t) becomes

$f(t)=0.4e^{-0.4t}$

<h3>Step 2</h3>

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

$\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt$

which is equal to 0.01

<h3>Step 3</h3>

Solve the equation for x

$\int\limits^{\infty}_x {0.4e^{-0.4t}} \, dt =0.01\\\\\frac{0.4e^{-0.4t}}{-0.4}=0.01\\\\-e^{-0.4t} |^\infty_x =0.01\\\\e^{-0.4x}=0.01$

Take natural log on both sides

$ln (e^{-0.4x})=ln(0.01)\\-0.4x=ln(0.01)\\-0.4x=-4.61\\x= 11.53$

<h3>Results</h3>

The costumer has to wait x = 11.53 mins ≅ 12 mins to get a free hamburger

3 0

3 years ago

Let P be the set of polynomials. Let a, b, c, and d be elements of P such that band d are non-zero elements of P. Which of the f

lozanna [386]

Answer:

D. The sum is a rational expression.

Step-by-step explanation:

the given expression is a/b +c/d

so in the question it is given that b and d are non zero values

a/b is rational number and c/d is a rational number

so if both are rational number , so we know that the sum of rational number is also a rational number.

The right option is D. The sum is a rational expression

7 0

3 years ago

If g(x) = 1 - ¾ x <br> find: -5g(4) - 1

cricket20 [7]

Answer:

<u>-</u><u>5</u><u>g</u><u>(</u><u>4</u><u>)</u><u> </u><u>-</u><u> </u><u>1</u><u> </u><u>is</u><u> </u><u>9</u>

Step-by-step explanation:

$g(x) = 1 - \frac{3}{4} x$

when x is 4:

$g(4) = 1 - \frac{3}{4} \times 4 \\ = 1 - 3 \\ = - 2$

therefore:

$- 5g(4) - 1 = - 5( - 2) - 1 \\ = 10 - 1 \\ = 9$

5 0

3 years ago

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Stels [109]

Answer:

step three is wrong

Step-by-step explanation:

just did it

7 0

3 years ago