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kupik [55]
4 years ago
11

What is the first day of spring

Mathematics
2 answers:
nasty-shy [4]4 years ago
8 0

Answer:

The first day of spring is  Thursday, March 19th.

The first day of summer is June 20th. So, Spring ends on June 20th.

Step-by-step explanation:

<em>I looked it up on the internet instead of asking on brainly.</em>

8090 [49]4 years ago
4 0

Answer:March 19-June 20

Step-by-step explanation:

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Use expressions for odd integers to confirm the conjecture that the product for two odd integers is an odd integer.
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k, n - integers  

2k+1  - an odd integer

2n+1  - another odd integer

The product of them:

  (2k + 1)(2n + 1) =

= 4kn + 2k + 2n + 1 =

= 2(2kn + k + n) + 1

The product of integers (2kn) is integer

and the sum of them (2kn+k+n) also is integer

So  (2k + 1)(2n + 1)  = 2(2kn + k + n) + 1  is an odd integer

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4 years ago
Suppose that the times required for a cable company to fix cable problems in its customers’ homes are uniformly distributed betw
vampirchik [111]

Answer:

a) 60% probability that a randomly selected cable repair visit will take at least 50 minutes

b) 60% probability that a randomly selected cable repair visit will take at most 55 minutes.

c) The expected length of the repair visit is 52.5 minutes.

d) The standard deviation is 7.22 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

For this problem, we have that:

Uniformly distributed between 40 and 65 minutes, so a = 40, b = 65

(a) What is the probability that a randomly selected cable repair visit will take at least 50 minutes?

Either it takes less than 50 minutes, or it takes at least 50 minutes. The sum of the probabilities of these events is decimal 1. So

P(X < 50) + P(X \geq 50) = 1

The intervals can be open or closed, so

P(X < 50) = P(X \leq 50)

We have that

P(X \geq 50) = 1 - P(X < 50)

P(X < x) = \frac{50 - 40}{65 - 40} = 0.4

P(X \geq 50) = 1 - P(X < 50) = 1 - 0.4 = 0.6

60% probability that a randomly selected cable repair visit will take at least 50 minutes

(b) What is the probability that a randomly selected cable repair visit will take at most 55 minutes?

This is P(X \leq 55)

P(X \leq 55) = \frac{55 - 40}{65 - 40} = 0.6

60% probability that a randomly selected cable repair visit will take at most 55 minutes.

(c) What is the expected length of the repair visit?

The mean of the uniform distribution is:

M = \frac{a+b}{2}

So

M = \frac{40+65}{2} = 52.5

The expected length of the repair visit is 52.5 minutes.

(d) What is the standard deviation?

The standard deviation of the uniform distribution is

S = \sqrt{\frac{(b-a)^{2}}{12}}

So

S = \sqrt{\frac{(65-40)^{2}}{12}}

S = 7.22

The standard deviation is 7.22 minutes.

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3 years ago
Samantha owns a small coffee shop and needs to borrow money for improvements and equipment upgrades. After looking at her financ
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Which relation is a function?
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C.) or the third one

Step-by-step explanation:

Each input has one output.

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