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3 years ago

Which expression is equivalent to 4f + f2 + 3?

Mathematics

1 answer:

Effectus [21]3 years ago

4 0

Answer:

6f + 3

Step-by-step explanation:

so in order to get a equation that is equivalent to 4f + f2 + 3 is you have to simplify the expression by adding numbers to numbers and variables to variables.

so we are going to add 4f and 2f together:

(4f + f2) + 3

And you get the expression:

6f + 3

I hope this helps you!!

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Aria paid $75,000 for her house. its property value increased by 2.2% per year. when aria sold her house after eleven years, how

Wewaii [24]

Answer:

Step-by-step explanation:

Converting percent to decimal : 2.2/100 = 0.022

Finding 2.2$ of $75k : 75,000 x 0.022 = $1,650 (also the increase in one year)

Finding how much it was worth after 11 years :

(75,000 x 0.022) x 11 = $18,150 or 1,650 x 11 = $18,150

Now add the product to the regular amount to find out the answer:

75,000 + 18,150 = $93,150 (which is how much it increased after 11 years)

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2 years ago

Diego had $21.32 and gave $9.50 to Elena. How much did he have left?

Charra [1.4K]

Answer:

11.82

Step-by-step explanation: I know this because 21.32-9.50= 11.82

7 0

3 years ago

Refer to the triangle below what is the volume of X. 45° 60°

RUDIKE [14]

Answer:

x = 75

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

Subtract the sum of the given angles from 180 for x

x = 180° - (60 + 45)° = 180 - 105° = 75°

5 0

3 years ago

In simplest radical form, what are the solutions to the quadratic equation 6 = x2 – 10x?

vichka [17]

Answer:

$x = 5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}$

Step-by-step explanation:

We need to solve the quadratic equation

6 = x^2 -10x

Rearranging we get,

x^2-10x-6=0

Using quadratic formula to solve the quadratic equation

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= 1, b =-10 and c=6

Putting values in the quadratic formula

$x=\frac{-(-10)\pm\sqrt{(-10)^2-4(1)(-6)}}{2(1)}\\x=\frac{10\pm\sqrt{100+24}}{2}\\x=\frac{10\pm\sqrt{124}}{2}\\x=\frac{10\pm\sqrt{2*2*31}}{2}\\x=\frac{10\pm\sqrt{2^2*31}}{2}\\x=\frac{10\pm2\sqrt{31}}{2}\\x = 5\pm\sqrt{31}$

So, $x=5+\sqrt{31}\,\, and\,\, x=5-\sqrt{31}$

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What is perimeter of 4 inch square

Kobotan [32]

4*4 is you answer just times 4*4

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3 years ago

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