Weights were recorded for all nurses at a particular hospital, the mean weight for an individual nurse was 135 lbs. with a stand
1 answer:
population mean, μ =135
population standard deviation, σ = 15
sample size, n = 19
Assume a large population, say > 100,
we can reasonably assume a normal distribution, and a relatively small sample.
The use of the generally simpler formula is justified.
Estimate of sample mean
Estimate of sample standard deviation
Thus, using the normal probability table,
Therefore
The probability that the mean weight is between 125 and 130 lbs
P(125<X<130)=0.0731166-0.0018308
=0.0712858
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2. c = 47,000 × n, where c is the cost of n number of bears.
3. a) The cost to ride 5 rides = $20.50, the cost to ride 8 rides = $28.00
The equation for the pattern, C(x) = 15.50 + 2.50 (r - 3), where C is the cost and r is the number of rides.
b) The cost to ride 12 rides = $36.00.
Step-by-step explanation:
Step 1; To find the cost of one bear, we divide the cost of bears by the number.
If 4 bears cost $188,000, 1 bear costs = = $47,000.
If 7 bears cost $329,000, 1 bear costs = = $47,000.
So the equation is c = 47,000 × n, where c is the cost to buy n bears.
Step 2; For every additional ride, the price increases by $2.50. So the equation for the pattern is C(x) = 13.50 + 2.50 (x - 3).
When the number of rides is 5, C(5) = 15.50 + 2.50 (5-3) = 15.50 + 2.50 (2) = 15.50 + 5.0 = $20.50.
When the number of rides is 8, C(8) = 15.50 + 2.50 (8-3) = 15.50 + 2.50 (5) = 15.50 + 12.50 = $28.00.
When the number of rides is 12, C(12) = 15.50 + 2.50 (12-3) = 15.50 + 2.50 (9) = 13.50 + 22.5 = $36.00.