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Makovka662 [10]
2 years ago
15

Part A Mr. Bade spends an average of $42.50 during a five-day workweek on lunch.if he eats every day during his 5-day workweek,

what is the average cost for one lunch?
Part B. If he started taking lunch to work two days out of five, how much would Mr. Bade save? ​
Mathematics
2 answers:
trasher [3.6K]2 years ago
4 0

Answer:

Part A: He spends an average of $8.50 per day

Part B:  He would save $17 per week

Step-by-step explanation:

givi [52]2 years ago
4 0

Answer:

Cho, wt.f is going on in ch.at!?

Step-by-step explanation:

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3 0
3 years ago
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-3^(-x)-6=-3^x+10<br><br>Solve the equation below for x by graphing plz
vitfil [10]
To graph it, just graph y=-3^{-x}-6 and y=-3^x+10 and see where they intersect

I would like to solve it by using math and not graphing
if you don't want to see the math, just don't scroll down
the graphical meathod is above, first line, just read it

hmm
multiply both sides by -1
3^{-x}+6=3^x-10
multiply both sides by 3^x
3^0+6(3^x)=3^{2x}-10(3^x)
1+6(3^x)=3^{2x}-10(3^x)
minus 1 from both sides and minus 6(3^x) from both sides
0=3^{2x}-16(3^x)-1
use u subsitution
u=3^x
we can rewrite it as
0=u^2-16u-1
now factor
I mean use quadratic formula
for ax^2+bx+c=0 x=\frac{-b+/-\sqrt{b^2-4ac}}{2a}
so for 0=u^2-16u-1, a=1, b=-16, c=-1
u=\frac{-(-16)+/-\sqrt{(-16)^2-4(1)(-1)}{2(1)}
u=8+/-\sqrt{65}
remember that u=3^x so u>0
if we have u=8+√65, it's fine, but u=8-√65 is negative and not allowed
so therfor
u=8+\sqrt{65}=3^x
8+\sqrt{65}=3^x
if you take the log base 3 of both sides you get
log_3(8+\sqrt{65})=x
if you use ln then
ln(8+\sqrt{65})=xln(3)
then
\frac{ln(8+\sqrt{65})}{ln(3)}=x

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SCORPION-xisa [38]
<h2>3.14 units²</h2><h3><em>(Assuming pi equals 3.14)</em></h3><h3><em></em></h3><h3>A = pi(radius²)</h3><h3></h3><h3>1² = 1</h3><h3>1 x 3.14 = 3.14</h3>
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C= -1 because when you add 38 to the other side you are left with -75c=75 then divide by -75 and you are left with -1
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