Answer:
t=0
Step-by-step explanation:
r=<+1,>
by differentiating the r vector component by component
r' = <2at, 1>
Two vector are orthogonal when the dot product between them is zero, so:
r'·r=0
<+1,>·<2at, 1>=2+2at+t=0
common factor
t(+2a+1)=0
Then, the only real value for t is zero.
-> t=0
To find the answer to this question, we must know what an intercept is. An intercept is a point where a line (or something else) touches an axis. For example, the y intercept is the point (or points) where the line would touch the y axis. To find the x and y intercepts for this graph, we just need to look at where the points of intersection are. In addition, the intercept of an axis has the other value equal to 0. That means that the y intercept would have an x value of 0 and the x intercept would have a y value of 0.
Now we have to look at the points. The y axis is the horizontal axis, and the line seems to intersect it at the point 2.5. Since we know that the x value is 0, that means that the y intercept is (0, 2.5). Now onto the x intercept. We see that the line touches the x axis at the point 3.5, meaning that the x intercept is (3.5, 0).
To solve these type of problems is to simply invert the number after the division sign and multiply
Just make a best guess on the graph where the fraction should be