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ivanzaharov [21]
3 years ago
12

Solve each of the following equations for xx. 2^x+1 = 32

Mathematics
2 answers:
Delvig [45]3 years ago
8 0

Answer:

x= 4

Step-by-step explanation:

2∧(x+1) = 32 = 2∧5

x+1 = 5

x= 4

arlik [135]3 years ago
7 0

Answer:

just go whith ur gut

Step-by-step explanation:

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If c = the number of cars in a parking lot, which algebraic expression
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c+9

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Help please and thanks! I always give brainliest!
Tju [1.3M]

Answer:

x=18, y=9

Step-by-step explanation:

The lines of y+3 and 12 look equal to each other. So do x-3 and 15. Because of this, we set each equal to each other and solve.

solving for x:

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Please help me out with this!!<br> BRAINLIEST AVAILABLE!!
lapo4ka [179]

Answer:

xy = 1

k = 79

Step-by-step explanation:

Question One

The first and third frames look to me to be the same. I'll treat them that way.

y = x^2                        Equate y = x^2 to the result of 2y + 6 = 2x + 6

2y + 6 = 2(x + 3)         Remove the brackets

2y + 6 = 2x + 6           Subtract 6 from both sides

2y = 2x                       Divide by 2

y = x

Now solve these two equations.

so x^2 = x                  

x > 0

1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is

x(x) = x                           Divide both sides by x            

x = 1                            

y = x^2                           Put x = 1 into x^2

y = 1^2                           Solve

y = 1                      

The second solution is

(1,1)

xy = 1*1

xy = 1

Answer: A

Question Two

square root(k + 2) - x = 0

Subtract x from both sides

sqrt(k + 2) = x                Square both sides

k + 2 = x^2                    Let x = 9

k + 2 = 9^2                    Square 9

k + 2 = 81

k = 81 - 2

k = 79

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