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4 years ago

Plz help i have no idea how to do this!!!

Mathematics

1 answer:

Fittoniya [83]4 years ago

4 0

Hello!

The interquartile range(IQR) is the difference between the third and first quartiles. In the box and whisker plot, this is how long the box is. As you can see, it goes from 7 to 12. We subtract, giving us 5.

Therefore, your answer is C) 5.

I hope this helps!

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A rectangular parcel of land has an area of 8,000 ft2. a diagonal between opposite corners is measured to be 10 ft longer than o

lapo4ka [179]

Answer:

Step-by-step explanation:

Let the area of the rectangle be Length × width

LW = 8000

If the diagonal is 10feer greater than one of its length then:

D = 10+L

Diagonal is represented using the Pythagoras theorem as shown:

D² = L²+W²

(10+L)²= L²+W²

100+20L +L² = L²+W²

From LW = 8000

W = 8000/L

100 + 20L = (8000/L)²

100 +20L = 64,000,000/L²

Cross multiply

100L² + 20L³ = 64,000,000

2L³+10L² = 6,400,000

L³+5L² = 3200000

L³+5L² -3200000 = 0

5 0

4 years ago

Read 2 more answers

HELP ASAP MARKING BRAINLEST<br><br> use the diagram to write the standard equation of the circle.

barxatty [35]

Answer:

your answer is:

(x-2)^2 +(y-2)^2=16

Hope this helps.

Brainliest plz :)

8 0

3 years ago

There are two peice pf gold and silver alloy. The ratio between the gold and silver in the first piece is 2:3, in the second pei

STALIN [3.7K]

Answer:

1 grams of one of the alloy; and
7 grams of the other corresponding alloy.

Step-by-step explanation:

The ratio between the gold and silver in the first piece = 2:3

The ratio between the gold and silver in the second piece =3:7

The ratio in the mixture = 5:11

We want to have 8 gram of the new mixture.

Let the gram of alloy taken from the first piece=x

Therefore: gram of alloy would be taken from the second piece=(8-x)

This gives:

$\dfrac{2}{5}x+ \dfrac{3}{10}(8-x)=\dfrac{5}{16}*8$

We simplify the equation above for the value of x.

$\dfrac{2x}{5}+ \dfrac{3(8-x)}{10}=\dfrac{5}{2} \\\dfrac{4x+24-3x}{10}=\dfrac{5}{2}\\\dfrac{x+24}{10}=\dfrac{5}{2}\\2x+48=50\\2x=50-48\\2x=2\\x=1$

Therefore to create 8 gram of gold and silver alloy with gold-silver ratio 5:11, we take 1 grams of one of the alloy and 7 grams of the other alloy.

3 0

3 years ago

SOLVE OR SIMPLIFY THIS!! -6-(2x+7)=-2(x+6)-1

Oliga [24]

$\\ \sf\longmapsto -6-(2x+7)=-2(x+6)-1$