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cricket20 [7]
2 years ago
5

The function f(x) is given by the set of ordered pairs.

Mathematics
1 answer:
Lana71 [14]2 years ago
8 0

The equation that is true and one that matches the set of ordered pairs of functions is option C. f (0) = 6

<h3>What is the equation about?</h3>

Note that a function can be made to be a given set of ordered pairs such as the ordered pairs (2,4), (3,5), (4,6)  can have  input functions of ​​(as domain) 2,3,4 and output functions of ​​(as range) of 4,5,6.

So when you see the ordered pairs. {(1,0), (–10,2), (0,6), (3,17), (–2, –1)} one can see that the option that matches to the set of ordered pairs of functions above is f (0) = 6 value x = 0, f (x) = y = 6, ordered pairs (0.6)

See full question below

The function f (x) is given by the set of ordered pairs. {(1,0), (–10,2), (0,6), (3,17), (–2, –1)}:Which equation is true?

f(-10)=1

f(2)=-10

f(0)=6

f(1)=-10

The answer choices are :

f (-10) = 1 values ​​x = -10, f (x) = y = 1, ordered pairs (-10,1)

f (2) = - 10 values ​​x = 2, f (x) = y = -10, ordered pairs (2, -10)

f (0) = 6 value x = 0, f (x) = y = 6, ordered pairs (0.6)

f (1) = - 10 values ​​x = 1, f (x) = y = -10, ordered pairs (1, -10)

Learn more about ordered pairs from

brainly.com/question/6200217

3SPJ1

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\begin{gathered} sinA=\frac{a}{c} \\ \sin15^{\circ}=\frac{3}{c} \\ c=\frac{3}{\sin15^{\circ}} \\ c=11.59 \\ c\approx11.6 \end{gathered}

Using the trigonometric ratio,

\begin{gathered} \tan A=\frac{a}{b} \\ \tan15^{\circ}=\frac{3}{b} \\ b=\frac{3}{\tan15^{\circ}} \\ b=11.19 \\ b\approx11.2 \end{gathered}

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Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt

Both integrals are quite immediate: you only need to use the power rule

\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}

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