All categories

2 years ago

Solve the equation. a² = 0.16

Mathematics

1 answer:

Kobotan [32]2 years ago

6 0

Take the square root of both sides to solve and you get a= 0.4,-0.4

You might be interested in

If my equation is ax^2+bx+c=0 how would the c end up on the right side and become -c?

Vaselesa [24]

By subtracting c on both sides

7 0

3 years ago

Point Q is the center of dilation. Lines segment S U is dilated to form line segment S prime U prime. The length of Q S is 3 .2

tia_tia [17]

Answer:

Option C.

Step-by-step explanation:

It is given that the dilation rule is $D_{Q,2.5}$ . It means the center of dilatation is point Q and scale factor is 2.5.

Scale factor is the ratio of distance from center to the image of a point and distance from center to the corresponding point.

$\text{Scale factor}=\dfrac{QU'}{QU}$

It is given that QU=4 and scale factor = 2.5.

$2.5=\dfrac{QU'}{4}$

Multiply both sides by 4.

$2.5\times 4=QU'$

$10=QU'$

We know that

$UU'=QU'-QU$

$UU'=10-4$

$UU'=6$

The distance between U' and U is 6 units.

Therefore, the correct option is C.

8 0

3 years ago

Read 2 more answers

Carlos is using the quadratic formula to find the solutions of y=3x^2-5x-2. Which of the following will simplify to the correct

Nana76 [90]

Answer:

$Fx=\frac{5\pm\sqrt{25+24} }{6}$

Step-by-step explanation:

A quadratic equation in one variable given by the general expression:

$ax^2+bx+c$

Where:

$a\neq 0$

The roots of this equation can be found using the quadratic formula, which is given by:

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

So:

$y(x)=3x^2-5x-2=0$

As you can see, in this case:

$a=3\\b=-5\\c=-2$

Using the quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}=\frac{-(-5)\pm\sqrt{(-5)^2-4(3)(-2)} }{2(3)}=\frac{5\pm\sqrt{25+24} }{6}$

Therefore, the answer is:

$Fx=\frac{5\pm\sqrt{25+24} }{6}$

4 0

2 years ago

Based on the given information, which conjecture is invalid?

a_sh-v [17]

Valid based on the given information. If not, write invalid. ... So, the statement is invalid. Determine .....disprove a conjecture reached using inductive or deductive .

3 0

3 years ago

2x^2y^3z^2 · 4xy^4x^2 Multiply and simplify

Advocard [28]

Take out the constants

(2 × 4)x^2xx^2y^3y^4z^2

Simplify 2 × 4 to 8

8x^2xx^2y^3y^4z^2

Use the Product Rule: x^ax^b = x^a + b

8x^2 + 1 + 2y^3 + 4z^2

Simplify 2 + 1 + 2 to 5

8x^5y^3 + 4z^2

Simplify 3 + 4 to 7

8x^5y^7z^2

6 0

2 years ago