I'm guessing you're asking what shape do you get if you cut a hexagon is cut into sixths.
If this hexagon is a regular hexagon, then the shapes would be equilateral triangles.
Total pressure is constant and PT = P = 1/2*ρ*v^2
So p1 + 1/2*ρ*v1^2 = p2 + 1/2*ρ*v2^2 and from continuity we have ρ*A1*v1 = ρ*A2*v2
So v2 = v1*A1/A2 since r2 = 2r1 then A2 = 4A1
so v2 = v1/4
Now from above p2 = p1 + 1/2*ρ*v1^2 - 1/2*ρ*v2^2 = p1 + 1/2*ρ*v1^2 - 1/2*ρ*v1^2/4^2
So p2 = 3.0x10^4Pa + 1/2*1000kg/m^3*(12m/s)^2 - 1/2*1000kg/m^3*12^2/16
= 9.75x10^4Pa = 9.8x10^4Pa
Answer:
4 cents
Step-by-step explanation:
4.50 divide by is .9 and 7.52 divide by 8 is .94
Answer:
3:4 i think
Step-by-step explanation:
3 4 is the answer
