Answer: (a) e ^ -3x (b)e^-3x
Step-by-step explanation:
I suggest the equation is:
d/dx[integral (e^-3t) dt
First we integrate e^-3tdt
Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.
(b) to differentiate the integral let x = t, and substitute into the expression.
Therefore dx = dt
Hence, d/dx[integral (e ^-3x dx)] = e^-3x
Answer:
T'
Step-by-step explanation:
See the diagram attached.
This is a unit circle having a radius (r) = 1 unit.
So, the length of the circumference of the circle will be 2πr = 2π units.
Now, the point on the circle at a distance of x along the arc from P is T.
Therefore, the point on the circle at a distance of 2π - x along the arc from P will be T' , where, T' is the image of point T, when reflected over the x-axis. (Answer)