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oksano4ka [1.4K]
3 years ago
7

Convert this ARMv8 machine code into ARMv8 Assembly Language instructions. Your final answers should use the register names, not

the numbers (i.e. X2, not 2). Also, values which represent absolute addresses (if any) should be converted into the full 32-bit (or 64-bit) address. a. 0x0000000080001294: EB01001F.b. 0x0000000080001298: 5400006A.c. 0x000000008000129C 91000400.d. 0x00000000800012A0 17FFFFFD.e. 0x00000000800012A4 D61F03C0.

Computers and Technology
1 answer:
kvv77 [185]3 years ago
7 0

Answer:

Detailed answer is provided in the explanation section

Explanation:

Conversion of ARMv8 machine code into ARMv8 Assembly Language instructions:

ARMv8 machine code ARMv8 Assembly Language

0x0000000080001294 : EB01001F                    CMP X0,X1

0x0000000080001298 : 5400006A

0x000000008000129C : 91000400

0x00000000800012A0 : 17FFFFFD

0x00000000800012A4 : D61F03C0

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  2. public class num8 {
  3.    public static void main(String[] args) {
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  18.        return first+second+third;
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  23.   public static double computeTotal(double decimalOne, double decimalTwo){
  24.        return decimalOne+decimalTwo;
  25.    }
  26.    public static void printAll( int first, int second, int third){
  27.        System.out.println("Number one, two and three are: "+first+" "+second+" "+third);
  28.    }
  29.    public static void printAll( int first, int second, int third, int fourth){
  30.        System.out.println("Number one, two and three and four are: "+first+" "+second+
  31.                " "+third+" "+fourth);
  32.    }
  33.   public static void printAll( int first, int second, int third, int fourth, int fifth){
  34.        System.out.println("Number one, two and three and four are: "+first+" "+second+
  35.                " "+third+" "+fourth+" "+fifth);
  36.    }
  37.    public static void printAll( double first, double second, double third){
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This solution is provided in Java:

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