You should boot into <u>safe mode</u> and disable the device or service when it causes the computer system to hang during a normal boot.
<h3>What is
safe mood?</h3>
Safe mood can be defined as a boot option in which the operating system (OS) of a computer system starts in <u>diagnostic mode</u> rather than in a normal operating mode, so as to enable the user correct any problems preventing the computer system to have a normal boot.
This ultimately implies that, safe mood is a diagnostic mode of the operating system (OS) of a computer system that is designed and developed to fix most problems within an operating system (OS) and for the removal of rogue software applications.
Read more on safe mood here: brainly.com/question/13026618
- The answer is "Option C" because the WMD is a freeware memory test software that works excellently.
- It is a comprehensive math question, and it is also quite straightforward to use.
- They suggest that you first test your ram with Memtest86, but you really should always test a second time with a different memory testing application to be certain.
- Microsoft Windows Diagnostic is the second tool, that scans your laptop's physical memory & identifies any faults.
- It requires a reboot to be used the system that will restart, and you'll be unable to your mouse in the Memory Diagnostic Tool.
The wrong choices can be defined as follows:
- In option a, it is wrong because the data warehouse transforms data into information that may be used by an organization's decision-making process.
- In option b, it is wrong because by using Metrics Collector Groups and logging the data, it was able to display real-time market data as well as collect and store data.
- In option d, it is wrong because this is a tool used in Windows, which displays detailed information about major events that have taken place on your machine.
- In option e, it is wrong because messages and trace logs could be viewed and sorted using the Log Viewer.
Learn more:
Memory Diagnostic: brainly.com/question/13606234
Explanation:
def letterDigitCount(j):
dic={"digits":0,"letters":0}
for a in j:
if a.isdigit():
dic["digits"]+=1
elif a.isalpha():
dic["letters"]+=1
return dic
This is calculated by raising 2 to the power of the number of bits.
2^12 = 4096
Is it where you can pick multiple answers