(3m^2-p)(3m-p^2)
You factor out the 3m^2 and p from the combined like terms and then group those into a factor and group the two identical factors together and (3m^2-p)(3m-p^2) is your answer.
<span>As only one team is to be made that means we have to choose 2 people from total 13 people. As the order that two people are selected does not matter here so we just have to make all possible combination of the team
So the answer is 13*12/2
answer= 78 ways</span>
Answer:
i would say B pls mark brainlest!
Ummmm................... I think you need to stick to the guidelines
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0 and 1 are neither prime nor composite. A prime is any number greater than 1 that has just 1 and itself as factors. Primes can only start at x > 1
When that happens (when you start with numbers greater than one) p^2 is a composite consisting of 2 primes, so any composite will obey the law that he number will have at least 3 factors making it up -- in this case p p^2 and 1.
So the answer to the question by definition is that 0 numbers can have the property of both p and p^2 to be prime.
