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2 years ago

2. Keeping in mind the context of this situation, what is the practical domain and practical range of this function?

Mathematics

1 answer:

Vilka [71]2 years ago

4 0

Since you are already given with how the graph looks like, and you are given the equation to verify the identity of the function, you can determine the domain and range by either inspection of the graph or substituting values to the function.
By inspection, the domain or the possible values of x is any real number from negative infinity to positive infinity or (-∞, +∞).
Again by inspection, the range or the possible values of y is any positive value or any real number greater than 0 to positive infinity or (0, +∞).

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If ZPQR measures 75 what is the measure of ZSQR?

slava [35]

Answer:

Since there's no given exact measurement. I'll assume that the angle is by default 180 degrees.

If angle PQR measure 75 degrees.

then the measurement of angle SQR will be:

Angle PQR = 75

Angle SQR = 180 - 75 degrees

Angle SQR = 105 degree

Step-by-step explanation:

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2 years ago

Estimate the quotient of 57.8 divided by 81

Rudik [331]

Right answer is 1.4013841

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3 years ago

Graph the line whose y-intercept is - 9 and whose x-intercept is 5.

Nostrana [21]

Answer:

y=1.8x-9

Step-by-step explanation:

if they are intercepts so the x/y will be zero, so in y intetceot the x is zero, and in the x itercept the y is zero.

0,-9

5,0

we calculate the slooe / rise

-9-0/0-5 = 1.8

we then use this formula

y-y1=rise(x-x1)

y-0=1.8(x-5)

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4 0

3 years ago

The thicknesses of 81 randomly selected aluminum sheets were found to have a variance of 3.23. Construct the 98% confidence inte

Yuliya22 [10]

Answer:

The confidence interval for the population variance of the thicknesses of all aluminum sheets in this factory is Lower limit = 2.30, Upper limit = 4.83.

Step-by-step explanation:

The confidence interval for population variance is given as below:

$[(n - 1)\times S^{2} / X^{2} \alpha/2, n-1 ] < \alpha < [(n- 1)\times S^{2} / X^{2} 1- \alpha/2, n- 1 ]$

We are given

Confidence level = 98%

Sample size = n = 81

Degrees of freedom = n – 1 = 80

Sample Variance = S^2 = 3.23

$X^{2}_{[\alpha/2, n - 1]} = 112.3288\\\X^{2} _{1 -\alpha/2,n- 1} = 53.5401$

(By using chi-square table)

[(n – 1)*S^2 / X^2 α/2, n– 1 ] < σ^2 < [(n – 1)*S^2 / X^2 1 -α/2, n– 1 ]

[(81 – 1)* 3.23 / 112.3288] < σ^2 < [(81 – 1)* 3.23/ 53.5401]

2.3004 < σ^2 < 4.8263

Lower limit = 2.30

Upper limit = 4.83.

8 0

2 years ago

-6(a + 8)<br> I need help!

Yuliya22 [10]

Answer: I got -6a + 48

Step-by-step explanation:I distributed and I got negative 6a because when you distributed the variable goes with whatever number is before it and I got 48 because -6 multiplied by 8 you get positive 48 because the 8 is bigger then the negative 6 so I don't know if your teacher wants you to solve for the answer but like I said I got -6a + 48

8 0

3 years ago