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sergeinik [125]
3 years ago
8

2. Keeping in mind the context of this situation, what is the practical domain and practical range of this function?

Mathematics
1 answer:
Vilka [71]3 years ago
4 0
Since you are already given with how the graph looks like, and you are given the equation to verify the identity of the function, you can determine the domain and range by either inspection of the graph or substituting values to the function.
By inspection, the domain or the possible values of x is any real number from negative infinity to positive infinity or (-∞, +∞).
Again by inspection, the range or the possible values of y is any positive value or any real number greater than 0 to positive infinity or (0, +∞).
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Speeding: On a stretch of Interstate-89, car speed is a normally distributed variable with a mean of 69.1 mph and a standard dev
Alborosie

Answer: 11.9%

Step-by-step explanation:

Given :  On a stretch of Interstate-89, car speed is a normally distributed variable with \mu=69.1 mph and \sigma=3.3 mph.

Let x be a random variable that represents the car speed.

Since , z=\dfrac{x-\mu}{\sigma}

z-score corresponds x = 73 , z=\dfrac{73-69.1}{3.3}\approx1.18

Required probability :

\text{P-value }: P(x>73)=P(z>1.18)\\\\=1-P(z

[using z-value table.]

Hence, the approximate percentage of cars are traveling faster than you = 11.9%

8 0
3 years ago
Can anyone help me with math , its a test.
Solnce55 [7]
Yea I can help:)! What is it???
4 0
3 years ago
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4.5, 3.25, 3.75, 3.25, 4.25, 3.5, 3.75, 4.25, 4.5, 2.5 <br><br> Whats the mean?
Alchen [17]

\frac{4.5 + 3.25 + 3.75 + 3.25 + 4.25 + 3.50 + 3.75 + 4.25 + 4.50 + 2.50}{10}  = 3.75
So; the answer is: 3.75
5 0
3 years ago
|x|, if x=10; .3; 0; −2.7; −9
alekssr [168]

Answer:

For \left | x \right | we will have positive values only.

\left | -2.7 |\right =2.7

\left | -9 |\right =9

Rest are positive so will give positive values out of the modulus function.

Step-by-step explanation:

The absolute value of any number is its positive value only.

As for example (-2.7) and (2.7) both are having equal distance from 0 in a number line, one on the left other on the right side of the number line but are equidistant from 0.

So absolute value of a number is its distance on number line from reference point 0.

One by one we will work with all of our question.

\left | 10 |\right =10

\left | 0.3 |\right =0.3

\left | 0 |\right =0

\left | -2.7 |\right =2.7

\left | -9 |\right =9

So we have to take the positive number out of the modulus function that is also called absolute value.

5 0
3 years ago
Evaluate - 2y + x(-3)<br> When x = -5 y = 3
Viktor [21]

Answer:

27

Step-by-step explanation:

2(6) + -5(-3)

= 12+15

= 27

4 0
3 years ago
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