3 years ago

What is the midpoint of the vertical line segment graphed below?

Mathematics

1 answer:

FromTheMoon [43]3 years ago

4 0

Answer:

(2, -2.5)

Step-by-step explanation:

4 to -9= 13 spaces

13/2=6.5

4-6.5=-2.5

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Ksju [112]

Answer:converge at $I=\frac{1}{3}$

Step-by-step explanation:

Given

Improper Integral I is given as

$I=\int^{\infty}_{3}\frac{1}{x^2}dx$

integration of $\frac{1}{x^2}$ is - $\frac{1}{x}$

$I=\left [ -\frac{1}{x}\right ]^{\infty}_3$

substituting value

$I=-\left [ \frac{1}{\infty }-\frac{1}{3}\right ]$

$I=-\left [ 0-\frac{1}{3}\right ]$

$I=\frac{1}{3}$

so the value of integral converges at $\frac{1}{3}$

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Step2247 [10]

Answer:

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Step-by-step explanation:

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f(2) = 10-12

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Step-by-step explanation:

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