Bella uses 1/5 cup of water for every 3/5 cup of sugar to make hummingbird food.

The slopes of the sides of quadrilateral ABCD are shown in the table below.

fredd [130]

Answer:

B) AB is parallel to CD, but AD is not parallel to BC.

Step-by-step explanation:

The options are:

A) AD is parallel to BC, but AB is not parallel to CD.

B) AB is parallel to CD, but AD is not parallel to BC.

C) AB is parallel to CD, and AD is parallel to BC.

D) AD is not parallel to BC, and AB is not parallel to CD.

AB and CD have the same slope, so they are parallel.

BC and AD have different slopes, so they are not parallel.

Therefore, the answer is B.

3 0

3 years ago

Which equation shows 4n=2(t-3) solves for t?

noname [10]

Answer:

t = 2n + 3

Step-by-step explanation:

Given

4n = 2(t - 3) ← divide both sides by 2

2n = t - 3 ( add 3 to both sides )

2n + 3 = t

5 0

4 years ago

A client has requested to have a stamped concrete patio put in their backyard. The plan indicates that the patio will be 16 feet

Ainat [17]

Answer:

59

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Circumference of a circular disc is 157 cm, find its radius

Zielflug [23.3K]

Answer:

Owwwww would be a good time

7 0

3 years ago

Read 2 more answers

It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So $\mu = 373, \sigma = 67$

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So $n = 5, s = \frac{67}{\sqrt{5}} = 29.96$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 373}{29.96}$

$Z = 1.23$

$Z = 1.23$ has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So $\mu = 526, \sigma = 107$