Answer: 23
When using multiplication with brackets, you multiply the number by all the numbers within the bracket before adding them together.
Therefore when it is 8(7 + 23) it basically means: 8(7) + 8(23)
b = number of tickets sold before
a = number of tickets sold after
cost of a ticket = number of tickets times cost per ticket
before cost = 39.95b
after cost = 54.95a
total cost = 925000
39.95b + 54.95a = 925000
total number tickets = 20000
b + a = 20000
we have
39.95b + 54.95a = 925000
b + a = 20000
multiply second equation by -39.95 and add to first equation
39.95b + 54.95a = 925000
-39.95b-39.95a = -799000 +
0b+15a = 126000
15a = 126000
divide bot sides by 15
a = 8400
sub back
b + a = 20000
b+8400 = 20000
minus 8400 both sides
b = 11600
11,600 tickets sold before
8400 tickets sold after
¾ an hour is 45 minutes
So to have your answers you need to do a cross product :
45 minutes —> 2/3 of a chapter
60 minutes —> X of a chapter
((2/3) • 60) / 45
40/45 = 8/9
Answer : You read 8/9 of a chaper per hour! :)
Answer:
The correct answer would be A) (4, 49.6)
Step-by-step explanation:
In order to find the equation, we first have to start with the base form of direct variation.
y = kx
Now we input the k value.
y = 12.4x
Now that we have this, we can try the ordered pairs and look for which satisfies the equation.
y = 12.4x
49.4 = 12.4(4)
49.4 = 49.4
Since this is the true statement, this is the ordered pair that works.
Answer:
Step-by-step explanation:
The complete question is given thus:
Suppose that computer literacy among people ages 40 and older is being studied and that the accompanying tables describes the probability distribution for four randomly selected people, where x is the number that are computer literate. Is it unusual to find four computer literates among four randomly selected people?
x P(x)
0 0.16
1 0.25
2 0.36
3 0.15
4 0.08
ANSWER:
The odds that this will occur according to the chart are 0.08, or 8%, so although this is unlikely, it's not terribly unusual.
⇒ NO
So from the following we can say it is not unusual to find four (4) computer literates among four randomly selected people.
ok, so P(1) + P(2) + P(3) + P(4) + P(0) = 0.16+0.25+0.36+0.15+0.08 = 1
Whereas the chance of finding four (4) out of four (4) computer iteration is low when compared to other factors.
cheers i hope this helped !!
