Find the area and circumference of the 2 circles

Factor completely and then place the factor. in the proper location on the grid (4x-+3)(-2x-5)

Ivahew [28]

Yay, love these ones.

First of all, (4x-+3)(-2x-5) is the same as (4x-3)(-2x-5)
So the method for solving these can be remembered by FOIL.
F= Firsts O= Outsides I= Insides L= Lasts

In other words everything is multiplied by everything, for example:
4x * -2x and -3 * -5 is the firsts of the brackets multiplied and last of the brackets mulitplied

4x * -5 and 3 * -2x is the outsides of the brackets multiplied and the insides of the brackets multiplied

The SUM of FOIL is then added:
4x*-2x = -8x^2
-3*-5= 15
4x*-5=-20x
3*-2x=-6x
-8x^2 -20x -6x + 15 = 0
-8x^2 -26x + 15 = 0

So the factored of (4x-3)(-2x-5) = -8x^2 -26x + 15 = 0

So then you graph that equation on your given grid

8 0

3 years ago

What is the volume of the following rectangular prism?

tatiyna

Answer:

The answer is 220.5.

since there is a square in it you would multiply 5 1/4 * 5 1/4* 8

6 0

2 years ago

The weight of a radioactive isotope was 96 grams at the start of an experiment. After one hour, the weight of the isotope was ha

zimovet [89]

The starting weight of the radioactive isotope = 96 grams

Weight after one hour is half of the starting weight. So the weight of the radioactive isotope after 1 hour = 48 grams

After 2 hours the weight is half as compared to the weight after previous hour. So weight after 2 hours = 24 grams.

This means, after every hour the weight is being halved. The half life of radioactive isotope is one hour.

Since after every hour, the weight is being halved, the weight of the isotope can be modeled by an exponential equation.

So,

Initial Weight = W₁ = 96
Change factor = 1/2 = 0.5

The general equation of the sequence will be:

$\\ \\ W_{t}=96(0.5)^{t}$

Here t represents the number of hours. Using various values of t we can find the weight of the radioactive isotope at that time.

We can plot the sequence using the above equation. The graph is attached below.

3 0

3 years ago

Read 2 more answers

the north pole is in the middle of the ocean. A person at sea level at the north pole would be 3,949 miles from the center of th

musickatia [10]

Answer:

7,897.30 miles

Step-by-step explanation:

It is given that the North Pole is at a distance of 3,949 miles from the center of the earth.

We also know that the sea floor is below 2.4 miles from the sea level.

It is given that a submarine is located at the sea floor near North Pole. Hence, the distance of the submarine from the center of the earth would be

3949 - 2.4 = 3946.6 miles.

On the other hand, the South Pole is given to be at an elevation of 1.7 miles from the sea level.

Since we know that the sea level is at a distance of 3949 miles from the center of the earth, we can immediately calculate the distance of the South Pole from the center of the earth to be

3949 + 1.7 = 3950.7 miles.

Putting all of this together, we see that the center of the earth is at a distance of 3946.6 miles from the submarine near the North Pole, and the center of the earth in turn is 3950.7 miles from the South Pole.

Hence, the distance between the submarine and a person on the South Pole = 3946.6 + 3950.7 = 7897.3 miles.