Be more specific. Like what is it asking you to do ? I'm trying to help. :)
Answer:
Step-by-step explanation:
All the angles in a triangle have to add up to 180 degrees.
#17.)
45+50=95
180-95=85
x=85
#18.)
This one is a little different. The furthest two angles are complimentary which means that they add up to 180 degrees (a straight line.) Once you find the missing angle to that one, you can do the same thing as you did in #17.
180-118=62.
25+62=87
180-87=93
x=93
#21.)
For this one a slightly larger equation is needed. Since we don't have a definite number for the bottom left angle, we have to use x+2 as our number. We first have to find the bottom right angle though.
180-108=72
x+x+2+72=180
2x+74=180
2x=106
x=53
Answer: see proof below
<u>Step-by-step explanation:</u>
Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ
Use the Sum/Difference Identities:
sin(α + β) = sinα · cosβ + cosα · sinβ
cos(α - β) = cosα · cosβ + sinα · sinβ
Use the Unit circle to evaluate: sin45 = cos45 = √2/2
Use the Double Angle Identities: sin2Ф = 2sinФ · cosФ
Use the Pythagorean Identity: cos²Ф + sin²Ф = 1
<u />
<u>Proof LHS → RHS</u>
LHS: 2sin(45 + 2A) · cos(45 - 2A)
Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)
Unit Circle: 2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]
Expand: 2[(1/2)cos²2A + cos2A·sin2A + (1/2)sin²2A]
Distribute: cos²2A + 2cos2A·sin2A + sin²2A
Pythagorean Identity: 1 + 2cos2A·sin2A
Double Angle: 1 + sin4A
LHS = RHS: 1 + sin4A = 1 + sin4A 
Answer:
The 2017 year is out of proportion.
Step-by-step explanation:
That graph should be at about half to 3/4 the height of the average heights of the other bars.