First, let's put the second equation, <span>x-2.23y+10.34=0, in terms of y:
x - 2.23y +10.34 = 0
2.23y = x + 10.34
y = .45x + 4.64
Now we can substitute the right side of this equation for y in the first equation
</span><span>y=2x^2+8x
.45x + 4.64 = 2x^2 + 8x
Turn it into a quadratic by getting 0 on one side:
2x^2 + 8x - .45x - 4.64 = 0
2x^2 + 7.55x - 4.64 = 0 Divide both sides by 2
x^2 + 3.76x - 2.32 = 0
x =( -b +/- </span>√(b² - 4ac) ) / 2a
x =( -3.76 +/- √(14.14 + 9.28)) ÷ 2
x = .54 or -4.31
Plug the x values into y = .45x + 4.64
y = .45 (.54) + 4.64
y = 4.88 when x= .54
y = .45 (-4.31) + 4.64
y = 2.70 when x= -4.31
Solution set:
{ (0.54, 4.88) , (-4.31, 2.70) }
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Note: Let us consider, we need to find the gradient of line L.
Given:
The given equation of a line is:
The line L passes through the points with coordinates (- 3, 1) and (2, - 2).
To find:
The gradient of the given line and the gradient of line L.
Solution:
Slope intercept form of a line is:
...(i)
We have,
...(ii)
On comparing (i) and (ii), we get
Therefore, the gradient of the given line is -4.
The line L passes through the points with coordinates (- 3, 1) and (2, - 2). So, the gradient of line L is:
Therefore, the gradient of the line L is 
.
point K and J grew up together there like brothers , so I would say they would be the closer duo. Your welcome;)
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31% = 0.31 = 0.31 × 575 = 178.25
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