It would be two trapezoids and a rectangle + two triangles
Answer:
ok so here is the answer: n
hk
b
a
х
V
Angle a = 126. What is the measure of angle b? Explain how you calculated your answer.
Angle a = 126 Write an equation(s) in terms of b to find the measure of angle h.
Calculate the measure of angle h, using the equation(s) you wrote for Part B.
How would knowing the measure of angle y change the equation(s) you wrote in Part B to find the measure of angle h?
2021 Muminate Education Inc Your input: factor x2+4x+3.
To factor the quadratic function x2+4x+3, we should solve the corresponding quadratic equation x2+4x+3=0.
Indeed, if x1 and x2 are the roots of the quadratic equation ax2+bx+c=0, then ax2+bx+c=a(x−x1)(x−x2).
Solve the quadratic equation x2+4x+3=0.
The roots are x1=−1, x2=−3 (use the quadratic equation calculator to see the steps).
Therefore, x2+4x+3=1(x+1)(x+3).
(x2+4x+3)=1(x+1)(x+3)
Step-by-step explanation:
It is 4 5/16 (I’m positive)
Answer:
c) 255
Step-by-step explanation:
d isn't divisible by 5 and both a and b aren't divisible by 3
We'll first clear a few points.
1. A hyperbola with horizontal axis and centred on origin (i.e. foci are centred on the x-axis) has equation
x^2/a^2-y^2/b^2=1
(check: when y=0, x=+/- a, the vertices)
The corresponding hyperbola with vertical axis centred on origin has equation
y^2/a^2-x^2/b^2=1
(check: when x=0, y=+/- a, the vertices).
The co-vertex is the distance b in the above formula, such that
the distance of the foci from the origin, c satisfies c^2=a^2+b^2.
The rectangle with width a and height b has diagonals which are the asymptotes of the hyperbola.
We're given vertex = +/- 3, and covertex=+/- 5.
And since vertices are situated at (3,0), and (-3,0), they are along the x-axis.
So the equation must start with
x^2/3^2.
It will be good practice for you to sketch all four hyperbolas given in the choices to fully understand the basics of a hyperbola.
